The best way to obtain pure, solid household salt from a solid mixture of household salt and sand is to "add water, stir, filter and evaporate the filtrate".
<u>Option: C</u>
<u>Explanation:</u>
The salt and sand can be separated on the basis of solubility, as we know the salt is chemically known as sodium chloride, which have good solubility in water. The most general method is the mixture is taken into a flask or beaker and water is added with stirring, where salt get dissolved and sand remain as it is, because NaCl is capable enough to form hydrogen bonding with water, while sand have absence of such property. Then this solution containing insoluble sand is filtered by using filter paper. The sand is received in filter paper while filtrate in beaker is evaporated by boiling it in order to receive salt as residue.
The moles of fluorine present are 71/19 = 3.74
Now, we know that one mole of gas at 273 K and 101.3 kPa (S.T.P.) occupies 22.4 liters
Volume of 3.74 moles at S.T.P = 3.74 x 22.4
Volume = 83.776 L = 83,776 mL
Now, we use Boyle's law, that for a given amount of gas,
PV = constant
P x 6843 = 101.3 x 83776
P = 1,240 kPa
Answer:
-219.99kJ
Explanation:
The acronym '' NADH'' simply stands for what is known as coenzyme 1 with full meaning of Nicotinamide Adenine Dinucleotide Hydride. This substance is useful in the production of energy. The oxidation reaction of NADH causes it to produce NADP⁺ and the oxygen produces water when it is in the reduction process. The balanced equation for the oxidation reaction is given below as:
NADPH ---------------------------------------------------------------------> NADP⁺H⁺ + 2e⁻.
Also, the balanced equation for the reduction reaction is given below as:
O₂ + 2H⁺ + 2e⁻ --------------------------------------------------------------> H₂O.
It can be shown from the above REDOX reaction that the total number of electrons getting transferred is 2.
The Gibbs energy = -nFE. where n = 2, F = faraday's constant = 96485.3329 C and E = overall cell potential.
The overall cell potential = E[ reduction reaction] - E[oxidation reaction] = 0.82 - (- 0.32 ) = 1.14 V.
Hence, the Gibbs energy = - 2 × 96485.3329 × 1.14 = -219.99kJ
A laboratory report is an important part of the scientific process that communicate the important work that has been done.
<h3>How to depict the laboratory report?</h3>
Your information is incomplete. Therefore, an overview of a laboratory report will be given. The laboratory report is important for future studies a d experiments.
A laboratory report is broken down intosections such as title, abstract, introduction, methods, materials, results, discussion conclusion, and references.
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