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posledela
2 years ago
15

The population of a country grows exponentially at a rate of 1% per year. If the population was 35.7 million in the year 2010, t

hen what is the population size of this country in the year 2015
Mathematics
1 answer:
Lady_Fox [76]2 years ago
7 0

Answer:

37.52 million

Step-by-step explanation:

using,

A = A'(1+R/100)ⁿ............................. equation 1

Where A = population size in 2015, A' = Initial population, R = rate in percentage, n = number of times between 2010 and 2015.

Given: A' =35.7 million, R = 1%, n = 5.

Substitute these values into equation 1

A = 35.7(1+0.01)⁵

A = 37.52 million.

Hence the size of the population of the country in the year 2015 is 37.52 million

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Answer:

n=(\frac{2.33(1400)}{400})^2 =66.50 \approx 67

So the answer for this case would be n=67 rounded up

Step-by-step explanation:

Information given

\bar X represent the sample mean for the sample  

\mu population mean

\sigma=1400 represent the sample standard deviation

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Solution to the problem

The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}    (a)

And on this case we have that ME =400 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

The critical value for 98% of confidence interval now can be founded using the normal distribution. And the critical value would be z_{\alpha/2}=2.33, replacing into formula (b) we got:

n=(\frac{2.33(1400)}{400})^2 =66.50 \approx 67

So the answer for this case would be n=67 rounded up

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3 years ago
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