Answer:
Group 17 elements:
Flourine (F), Chlorine (Cl), Bromine (Br), Iodine (I), and Astatine (As).
Period 2 elements:
Lithium (Li), Beryllium (Be), Boron (B), carbon (C), Nitrogen (N), Oxygen (O), flourine (F), And Neon.
Answer:
D. Reduction takes place at the cathode, which is negatively charged.
Explanation:
In an electrolytic cell there are two electrodes; the cathode and the anode. The anode is the positive electrode while the cathode is the negative electrode. Oxidation occurs at the anode while reduction occurs at the cathode.
At the anode, species give up electrons and become positively charged ions while at the cathode species accept electrons and become reduced.
defective greatest formerly knows sd ghost;
One of the following substances would be the most soluble in CCl₄ is C₄H₁₀.
<h3>What is CCl₄?</h3>
CCl₄ is carbon tetra chloride is an organic compound with a sweet smell and colorless liquid.
It is used in liquid for refrigerator, as a pesticide, a propellant for aresol cans and in fire extinguisher, but it is very a harmful substance that why it is banned.
Thus, the substances would be the most soluble in CCl₄ is C₄H₁₀.
Learn more about carbon tetra chloride
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First convert mega grams to grams
(9.57x10^2)*(10^6)=957100000 grams
Then find the molar mass of nickel sulphate
Nickel Ni 3+ and sulphate SO4 2+
So formula= Ni2(SO4)3
So mr = (59*2) + (32*3) + (16*12)
= 406gmol-1
Moles = mass/mr
957100000/406
=2357389.163 moles
