Answer:
Explanation:
The angular frequency of the system is:
The frequency is:
The angular frequency is:
The spring constant is:
Balanced forces cause no change in motion, even if the object is moving.
Answer: v = (33320 - 340f2)/( f2 + 98)
Explanation: this question refers to Doppler effect, hence,
f1 = { V / (V - v)} x f2
f1 = 98Hz, f2 = 76 Hz, V = 340m/s, v = ?, fs = fsourcs
For f1,
98 = { 340 / (340 + v)} x fs ...(i)
for f2,
f2 = { 340 / (340 - v)} x fs ... (ii)
Divide (ii) by (i)
98/f2 = [{ 340 / (340 + v)} x fs]÷ [ 340 / (340 - v)} x fs]
98/f2 = {340 / (340 + v)} x fs x (340 - v)} / 340 x fs
98/f2 = (340 + v)/ (340 - v)
Cross multiplying
98(340 - v) = f2 (340 + v)
33320 - 98v = 340f2 + vf2
Collecting like terms
vf2 +98v = 33320 - 340f2
v(f2 +98) = 33320 - 340f2
v = (33320 - 340f2)/( f2 + 98)
What Newton discovered is that gravity extends throughout the universe.
<h3>What is gravity?</h3>
The term gravity refers to the force that acts on a body in the universe. It is gravity that makes an object to fall when it is thrown up. The force of gravity acts on every object in the universe and it extends through the universe.
Humans have always known about gravity when they fall from a height and when they threw things up. However, human did not know that gravity extends throughout the universe.
Thus, what Newton discovered is that gravity extends throughout the universe.
Learn more about gravity:brainly.com/question/4014727
#SPJ1
When the projectile is at its maximum height above ground, it's at the point
of changing from rising to falling. At that exact point, its vertical speed is zero,
so the 14 m/s must be all horizontal velocity. That's not going to change.
Since we need to consider changes in vertical speed now, we need to make
some assumption about where this is all happening, so that we know the
acceleration of gravity. I'll assume that it's all happening on or near the Earth,
and the acceleration of gravity is 9.8 m/s².
I'm also going to neglect air resistance.
a). 1.2 sec before it reaches its maximum height, the projectile is rising
at a vertical speed of (1.2 x 9.8) = 11.76 m/s.
The magnitude of its velocity is
the square root of (14² + 11.76²) = 18.28 m/s, directed about 40° above horizontal.
b). 1.2 sec after it reaches its maximum height, the projectile is falling
at a vertical speed of (1.2 x 9.8) = 11.76 m/s.
The magnitude of its velocity is
the square root of (14² + 11.76²) = 18.28 m/s, directed about 40° below horizontal.
===========================
In 1.2 second before or after zero vertical speed, an object in free fall moves
(1/2) (g) (t²) = (4.9) (1.2²) = 7.06 meters .
c). & d).
1.2 seconds before it reaches maximum height, the projectile is located at
x = -14 m
y = -7.06 m
e). & f).
1.2 seconds after it reaches maximum height, the projectile is located at
x = +14 m
y = -7.06 m .
I hope you recognize that 6 answers, plus a little bit of explanation,
all for 5 points, ain't too shabby. You made out well.
