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viktelen [127]
3 years ago
13

football player A has a mass of 110 kg is running on the field is velocity of 2 m/s football player B has a mass of 120 kg and a

stationary what if football player a collage of the football player babe what is the total momentum after the collision
Physics
1 answer:
valkas [14]3 years ago
7 0

Complete Question:

Football player A has a mass of 110 kg, and he is running down the field with a velocity of 2 m/s. Football player B has a mass of 120 kg and is stationary. What is the total momentum after the collision?

Answer:

Total momentum = 220 Kgm/s.

Explanation:

<u>Given the following data;</u>

For footballer A

Mass, M1 = 110kg

Velocity, V1 = 2m/s

For footballer B

Mass, M1 = 120kg

Velocity, V1 = 0m/s since he's stationary.

To find the total momentum;

Momentum can be defined as the multiplication (product) of the mass possessed by an object and its velocity. Momentum is considered to be a vector quantity because it has both magnitude and direction.

Mathematically, momentum is given by the formula;

Momentum = mass * velocity

a. To find the momentum of A;

Momentum \; A = 110 * 2

Momentum A = 220 Kgm/s.

b. To find the momentum of B;

Momentum \; B = 120 * 0

Momentum B = 0 Kgm/s.

c. To find the total momentum of the two persons;

Total \; momentum = Momentum \; A + Momentum \; B

Substituting into the equation, we have;

Total \; momentum = 220 + 0

<em>Total momentum = 220 Kgm/s. </em>

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Answer:

Number of electrons, n=9.98\times 10^{19}

Explanation:

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explained in attachment

Explanation:

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A box-shaped metal can has dimensions 5 in. by 19 in. by 4 in. high. All of the air inside the can is removed with a vacuum pump
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Answer:

The force is  F  =  1397 lb

Explanation:

From the question we are told that

    The length of the box is  l  =  19 \ in

    The width of the box is  w =  5 \ in

     The height is  h  =  4\ in

The pressure experience on one of the sides is mathematically represented as

     p = \frac{F}{A}

Where A is the area of the box which is mathematically evaluated as

    A =  l * w

substituting values

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This pressure is equivalent to the atmospheric pressure which has a constant value of  p = 14.7 pi

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To convert from Kg to g we multiply by 1000 (1 Kg = 1000 g)

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