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viktelen [127]
3 years ago
13

football player A has a mass of 110 kg is running on the field is velocity of 2 m/s football player B has a mass of 120 kg and a

stationary what if football player a collage of the football player babe what is the total momentum after the collision
Physics
1 answer:
valkas [14]3 years ago
7 0

Complete Question:

Football player A has a mass of 110 kg, and he is running down the field with a velocity of 2 m/s. Football player B has a mass of 120 kg and is stationary. What is the total momentum after the collision?

Answer:

Total momentum = 220 Kgm/s.

Explanation:

<u>Given the following data;</u>

For footballer A

Mass, M1 = 110kg

Velocity, V1 = 2m/s

For footballer B

Mass, M1 = 120kg

Velocity, V1 = 0m/s since he's stationary.

To find the total momentum;

Momentum can be defined as the multiplication (product) of the mass possessed by an object and its velocity. Momentum is considered to be a vector quantity because it has both magnitude and direction.

Mathematically, momentum is given by the formula;

Momentum = mass * velocity

a. To find the momentum of A;

Momentum \; A = 110 * 2

Momentum A = 220 Kgm/s.

b. To find the momentum of B;

Momentum \; B = 120 * 0

Momentum B = 0 Kgm/s.

c. To find the total momentum of the two persons;

Total \; momentum = Momentum \; A + Momentum \; B

Substituting into the equation, we have;

Total \; momentum = 220 + 0

<em>Total momentum = 220 Kgm/s. </em>

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Answer:

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Explanation:

First to calculate te initial speed we use the acceleration formula:

a= v1-v0/t

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v1 being the speed when Jill sees the pot

v0 when Jack sees it

and t the time between

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replacing

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For the second question we use the position formula setting y0 and t0 as the position and time when jack sees the pot. (and setting the positive axis downward I.E. one meter below jack would be 1m not -1m)

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You shoot an arrow into the air. Two seconds later (2.00 s) the arrow has gone straight upward to a height of 35.0 m above its l
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This question can be solved by using the equations of motion.

a) The initial speed of the arrow is was "9.81 m/s".

b) It took the arrow "1.13 s" to reach a height of 17.5 m.

a)

We will use the second equation of motion to find out the initial speed of the arrow.

h= v_it + \frac{1}{2}gt^2\\

where,

vi = initial speed = ?

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t = time interval = 2 s

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Therefore,

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<u>vi =  9.81 m/s</u>

b)

To find the time taken by the arrow to reach 17.5 m, we will use the second equation of motion again.

h= v_it + \frac{1}{2}gt^2\\

where,

g = acceleration due to gravity = 9.81 m/s²

h = height = 17.5 m

vi = initial speed = 9.81 m/s

t = time = ?

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Since time can not have a negative value.

Therefore,

<u>t = 1.13 s</u>

Learn more about equations of motion here:

brainly.com/question/20594939?referrer=searchResults

The attached picture shows the equations of motion in the horizontal and vertical directions.

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