Answer:
There is 5.72 grams of H2 formed
1) C+ H2O → CO + H2
2) We start with 34 grams of carbon that will react with an excess of H2O
3) 5.72 grams of H2
Explanation:
Step 1: Data given
Mass of carbon = 34.00 grams
H2O is in excess
Molar mass of C = 12 g/mol
Molar mass of H2O = 18.02 g/mol
Step 2: The balanced equation
C+ H2O → CO + H2
Step 3: What is the starting substance
We start with 34 grams of carbon that will react with an excess of H2O
Step 4: Calculate moles carbon
Moles C = mass C / molar mass C
Moles C = 34.00 grams / 12.00 g/mol
Moles C = 2.833 moles
Step 5: Calculate moles H2
Carbon is the limiting reactant.
For 1 mol Carbon we need 1 mol H20 to produce 1 mol CO and 1 mol H2
For 2.833 moles C we'll have 2.833 moles H2
Step 6: Calculate mass of H2
Mass H2 = moles H2 * molar mass H2
Mass H2 = 2.833 moles * 2.02 g/mol
Mass H2 = 5.72 grams of H2
