Explanation:
<em>5</em><em>0</em><em>0</em><em> </em><em>degre</em><em>e</em><em> </em><em>Celsius</em><em> </em><em> </em><em>be</em><em>cause</em><em> </em><em>we</em><em> </em><em>can</em><em> </em><em>see</em><em> </em><em>i</em><em>t</em><em> in</em><em> the</em><em> </em><em>tube</em>
830 mL. A 2.3 mol/L solution of CaCl2 has a volume of 830 mL
I am guessing that the concentration of your solution is 2.3 mol/L.
a) Moles of CaCl2
MM of CaCl2 = 110.98 g/mol
Moles of CaCl2 = 212 g CaCl2 x (1 mol CaCl2/110.98 g CaCl2)
= 1.910 mol CaCl2
b) Volume of solution
V = 1.910 mol CaCl2 x (1 L solution/2.3 mol CaCl2) = 0.83 L solution
= 830 mL solution
Answer: 1.31 × 10^47 sorry if its not the answer
Explanation:
