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arlik [135]
3 years ago
12

Which one of the following describe chemical properties? check all that apply. -water freezes at 0 degrees C. -sugar burns in ai

r to form water and carbon dioxide. -mercury is a liquid at room temperature . -Helium is the lightest monatomic element
Chemistry
1 answer:
uysha [10]3 years ago
8 0
I think the correct answer from the choices listed above is option C. The process that describes a chemical property of a substance is that when <span>sugar burns in air to form water and carbon. Hope this answers the question. Have a nice day.</span>
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How many neutrons does element X have if its atomic number is 35 and its mass number is 76?
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Formula for calculation of neutrons is Mass number - atomic number, here values are given. By putting values in formula 76-35= 41. Number of neutrons 41

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Alchemy is the process of trying to turn non-gold metals into gold. It was practiced hundreds of years ago by scientists who bel
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Alchemy is a practice of making gold from other metals.

Explanation:

Alchemy is a method which is practiced by the ancient scientists of Europe, Africa and Asia trying to produced gold from other metals. This method was failed to produced gold from metals and all scientist suggested that metals can not be converted into gold. Greeks were the people who presented the theory of alchemy in the first few centuries of CE.

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A balloon is filled to a volume of 700 mL at a pressure of 1.2 atm. The volume is increased 950 ml, what will be the new pressur
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2 years ago
A 1.52 g sample of KCIO3 is reacted according to the balanced equation below. How many liters of O2 is produced at a pressure of
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Answer:

0.486 L

Explanation:

Step 1: Write the balanced reaction

2 KCIO₃(s) ⇒ 2 KCI (s) + 3 O₂(g)

Step 2: Calculate the moles corresponding to 1.52 g of KCIO₃

The molar mass of KCIO₃ is 122.55 g/mol.

1.52 g × 1 mol/122.55 g = 0.0124 mol

Step 3: Calculate the moles of O₂ produced from 0.0124 moles of KCIO₃

The molar ratio of KCIO₃ to O₂ is 2:3. The moles of O₂ produced are 3/2 × 0.0124 mol = 0.0186 mol

Step 4: Calculate the volume corresponding to 0.0186 moles of O₂

0.0186 moles of O₂ are at 37 °C (310 K) and 0.974 atm. We can calculate the volume of oxygen using the ideal gas equation.

P × V = n × R × T

V = n × R × T/P

V = 0.0186 mol × (0.0821 atm.L/mol.K) × 310 K/0.974 atm = 0.486 L

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2 years ago
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