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Andreyy89
3 years ago
11

Describe how you would prepare your assigned ester from a carboxylic acid and an alcohol. You do not need to include a detailed

procedure, but you should include any necessary reagents or catalyst (solvents are not needed).
Chemistry
1 answer:
vesna_86 [32]3 years ago
8 0

Answer:

The general preparation of esters( for example ethyl ethanoate) is through a process known as ESTERIFICATION.

Explanation:

The formation of an ester by the reaction between an alkanol and an acid is known as esterification. This reaction is extremely slow and reversible at room temperature, and is catalyzed by a high concentration of hydrogen ions.

In the preparation of one of the simpler esters known as ETHYL ETHANOATE the reactants include ethanol(an alcohol) and glacial ethanoic acid(a carboxylic acid) in the presence of concentrated tetraoxosulphate VI acid as a CATALYST. Note that, a catalyst is any substance that is able to increase the rate of a chemical reaction.

The mixture is warmed in a water bath( hot but not boiling) for about 25 minutes. The mixture is poured into a beaker partially filled with a sodium or calcium chloride to remove interacted ethanol. The ethyl ETHANOATE floats on the mixture as oily globules.

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It looked like the continents fit together like puzzle pieces

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7 0
2 years ago
1.
Leya [2.2K]

Answer:

V₂ = 530.5 mL

Explanation:

Given data:

Initial temperature = 20.0°C

Final temperature = 40.0 °C

Final volume = 585 mL

Initial volume = ?

Solution:

Initial temperature = 20.0°C (20+273 = 293 K)

Final temperature = 40.0 °C (40+273 = 323 K)

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₁ = V₂T₁ /T₂  

V₂ = 585 mL × 293 K / 323 K

V₂ = 171405 mL.K / 323 K

V₂ = 530.5 mL

6 0
3 years ago
A teacher attaches two slinky springs to a fixed support. The springs are moved, as shown in the image. Wave A wave B What prope
Misha Larkins [42]

Answer:

a changes more because it going higher

Explanation:

6 0
3 years ago
Read 2 more answers
Compare 1 mole of H2, 1 mole of O2, and 1 mole of F2. (a) Which has the largest number of molecules? Explain why. (b) Which has
AURORKA [14]

<u>a) Answer: </u>

<em>Number of molecules in 1 mole</em>

<u>Explanation:</u>

a) Whether we take any of the substance among all three of the given substances they will have the same number of molecules in 1 mole of the substance is considered and the value for this will be 6.023 x 10^23

<u>b)  Answer: </u>

<em>In the given question </em><em>mass of the substance</em><em> which is </em><em>greatest</em><em> is asked for </em><em>one mole</em><em> and we also know that </em><em>mass of one mole is given by molar mass.  </em>

<u>Explanation:</u>

b) It is known that 31.98g/mol is the molar mass for oxygen which is greater than that of hydrogen while fluorine has a molar mass of 38.0 g/mol which on comparison shows that, it is the highest amongst all three.

3 0
3 years ago
Balancing chemical equations
kolbaska11 [484]

Answer:

2B2 + 3O2 → 2B2O3

Explanation:

Balance The Equation: B2 + O2 = B2O3

1. Label Each Compound With a Variable

  aB2 + bO2 = cB2O3

2. Create a System of Equations, One Per Element

  B: 2a + 0b = 2c

  O: 0a + 2b = 3c

3. Solve For All Variables (using substitution, gauss elimination, or a calculator)

  a = 2

  b = 3

  c = 2

4. Substitute Coefficients and Verify Result

  2B2 + 3O2 = 2B2O3

      L R

  B: 4 4 ✔️

  O: 6 6 ✔️

hope this helps!

7 0
2 years ago
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