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lakkis [162]
3 years ago
11

What describes this angle? Because I don’t know what the hell it means.

Mathematics
1 answer:
maw [93]3 years ago
5 0

Answer:

Less than a right angle.

Step-by-step explanation:

If you really think about it, a right angle is 90 degrees, and from the looks of it, that angle shown is an acute angle. Acute angles are always smaller than a right angle, so your answer is less than a right angle. :)

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What is the probability of landing on red and rolling a number greater than 2?
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3 years ago
Simplify 3x^2y^4 x 2x^6y
Feliz [49]

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6x^8y^5

Step-by-step explanation:

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8 0
3 years ago
HELP ME PLEASE IF YOU DO I WILK GIVE YOU POINTS <br><br> THANK YOU SO MUCH
blondinia [14]

Answer:

1. 54 2. 2$

Step-by-step explanation:

1. total students= 331

n.o of buses=6

now,

total no of students travelling through bus,

=331-7

=324

now,

324÷6

=54

2.

total money=24$

remaining money= 10$

spent money on pencil= 24-10$

= 14$

now,

7 pencils cost= 14$

1 pencil cost= 14÷7$

=2$

6 0
2 years ago
Let f (x) = 3x − 1 and ε &gt; 0. Find a δ &gt; 0 such that 0 &lt; ∣x − 5∣ &lt; δ implies ∣f (x) − 14∣ &lt; ε. (Find the largest
s344n2d4d5 [400]

Answer:

This proves that f is continous at x=5.

Step-by-step explanation:

Taking f(x) = 3x-1 and \varepsilon>0, we want to find a \delta such that |f(x)-14|

At first, we will assume that this delta exists and we will try to figure out its value.

Suppose that |x-5|. Then

|f(x)-14| = |3x-1-14| = |3x-15|=|3(x-5)| = 3|x-5|< 3\delta.

Then, if |x-5|, then |f(x)-14|. So, in this case, if 3\delta \leq \varepsilon we get that |f(x)-14|. The maximum value of delta is \frac{\varepsilon}{3}.

By definition, this procedure proves that \lim_{x\to 5}f(x) = 14. Note that f(5)=14, so this proves that f is continous at x=5.

3 0
3 years ago
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