You're provided a 0.50 M solution of HCl. How many moles of HCl are present in 25 ml of this solution?
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Answer:
Answer: There are 9 ways to make a single base mismatch, 27 ways to make a two base pair mismatch and, again, 27 ways to make a three base pair mismatch (and only 1 way to do it correctly). Q = e − U i k b T i ∑ = e − U zeromismatches k b T + 9 × e − U onemismatche k b T + 27 × e − U twomismatches k b T + 27 × e − U threemismatches k b T = e 0 k b T + 9 × e − 10 kJ / mol k b T + 27 × e − 20 kJ / mol k b T 27 × e − 30 kJ / mol k b T = 1 + 9 × (0.018) + 27 × (0.00033) + 27 × (0.000006) = 1 + (0.163) + (0.0089) + (0.00016) =1.17 p 0 = e − U 0 k b T Q = e − 0 k b T 1.17 = 1 1.17 = 0.853 => 85.3% Therefore, approximately 85.3% of all amino acids are translated faithfully. The redundancy built into the genetic code and other energetic considerations raise this number considerably.
Explanation:
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Answer:
hello your question is incomplete attached below is the complete question
Pyridinium ion is more soluble in 0.1 M HCL (aqueous solution) and this is because the Pyridine ion reacts with NaOH and after the reaction it comes out neutral.
N-acetyltyrosine methyl ester is more soluble in 0.1 M HCL while
B-napthol is more soluble in 0.1 M NaOH because it forms phenoxide ion
Explanation:
Pyridine ion is more soluble in 0.1 M HCL (aqueous solution) and this is because the Pyridine ion reacts with NaOH and after the reaction it comes out neutral.
N-acetyltyrosine methyl ester is more soluble in 0.1 M HCL while
B-napthol is more soluble in 0.1 M NaOH because it forms phenoxide ion
attached below is the remaining part of the solution
Answer: 111g S
Explanation:
SO2 you have = 665 g
SO2 molar mass = 64.066 g/mol
S molar mass = 32.065 g/mol