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Crank
3 years ago
10

A sample of gas has an initial volume of 25 L and an initial pressure of 3.5 Pa. If the pressure changes to 1.3 Pa, find the new

volume, assuming that the temperature remains constant.
Chemistry
1 answer:
lorasvet [3.4K]3 years ago
6 0
Since you are provided with the pressure and initial volume and told a standard temperature, you should use the Combined gas law. This is (P1 V1)/ T1 = (P2 V2)/ T2 
STP is 273 k for temperature, so plug in the values. 
(3.5 Pa * 25 L)/ 273 K =1.3 Pa * X L)/ 273 K.
(this is the left side>)0.32051= 1.3 X/ 273.  Multiply both sides by 273 to get rid of it on the right, which leaves you with
87.4999 = 1.3 X. Divide both sides by 1.3 and there you go, 

67.308 L
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To determine the enthalpy and entropy of dissolving a compound, you need to measure the Ksp at multiple _______. Then, plot ln(K
Aloiza [94]

Answer:

To determine the enthalpy and entropy of dissolving a compound, you need to measure the Ksp at multiple temperatures. Then, plot ln(Ksp) vs. 1/T. The slope of the plotted line relates to the enthalpy (ΔH) of dissolving and the intercept of the plotted line relates to the entropy (ΔS) of dissolving.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us use the thermodynamic definition of the Gibbs free energy and its relationship with Ksp as follows:

\Delta G=-RTln(Ksp)\\\\\Delta G=\Delta H-T\Delta S

Thus, by combining them, we obtain:

-RTln(Ksp)=\Delta H-T\Delta S\\\\ln(Ksp)=-\frac{\Delta H}{RT} +\frac{T\Delta S}{RT} \\\\ln(Ksp)=-\frac{\Delta H}{RT} +\frac{\Delta S}{R}

Which is related to the general line equation:

y=mx+b

Whereas:

y=ln(Ksp)\\\\m=-\frac{\Delta H}{R} \\\\x=\frac{1}{T} \\\\b=\frac{\Delta S}{R}

It means that we answer to the blanks as follows:

To determine the enthalpy and entropy of dissolving a compound, you need to measure the Ksp at multiple temperatures. Then, plot ln(Ksp) vs. 1/T. The slope of the plotted line relates to the enthalpy (ΔH) of dissolving and the intercept of the plotted line relates to the entropy (ΔS) of dissolving.

Regards!

8 0
3 years ago
Arizona was the site of a 400,000-acre wildfire in June 2002. How much carbon dioxide (CO2) was produced into the atmosphere by
kodGreya [7K]

Answer:

2.97 × 10¹³ g

Explanation:

First, we have to calculate the biomass the is burned. We can establish the following relations:

  • 2.47 acre = 10,000 m²
  • 10 kg of C occupy an area of 1 m²
  • 50% of the biomass is burned

The biomass burned in the site of 400,000 acre is:

400,000acre\times\frac{10,000m^{2} }{2.47acre} \times \frac{10kgC}{m^{2} } \times 50\% = 8.10 \times 10^{9} kgC

Let's consider the combustion of carbon.

C(s) + O₂(g) ⇒ CO₂(g)

We can establish the following relations:

  • The molar mass of C is 12.01 g/mol
  • 1 mole of C produces 1 mole of CO₂
  • The molar mass of CO₂ is 44.01 g/mol

The mass of  produced is CO₂:

8.10 \times 10^{12}gC \times \frac{1molC}{12.01gC} \times \frac{1molCO_{2}}{1molC} \times \frac{44.01gCO_{2}}{1molCO_{2}} =2.97 \times 10^{13} gCO_{2}

4 0
3 years ago
How does most ocean water return to the ocean in the water cycle?
abruzzese [7]

The sun, which drives the water cycle, heats water in the oceans. Some of it evaporates as vapor into the air. ... Most precipitation falls back into the oceans or onto land, where, due to gravity, the precipitation flows over the ground as surface runoff.

7 0
3 years ago
a solution is made by dissolving 21.5 grams of glucose (C6H12O6) in 255 grams of water. what is the freezing point depression of
Lesechka [4]
The freezing point depression of the solution or pure substance that is added with the solvent is calculated through the equation,
    
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where ΔT is the freezing point depression, Kf is the constant for water given to be -1.86°C/m and m is the molality of the solution. 

Molality is calculated through the equation,
    
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Calculation of molality is shown below.
    
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The freezing point depression is then,
    
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<em>Answer: -0.87°C</em>
3 0
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What is the period and atomic number of the atom with atomic number 46​
UNO [17]

Answer:

Atomic number: 46

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4 0
3 years ago
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