All categories

3 years ago

How are electrons arranged around the nucleus?

Chemistry

1 answer:

mrs_skeptik [129]3 years ago

7 0

There arranged in energy shells each shell has a limit to how many electrons they can carry this varies with element.

You might be interested in

You have 41.6 g of O2 gas in a container with twice the volume as one with CO2 gas in another container. The pressure and temper

prisoha [69]

Answer:

The mass of carbon dioxide is 28.6 grams

Explanation:

Step 1: Data given

Mass of O2 = 41.6 grams

Volume of the O2 container = 2V

Volume of the CO2 container = V

Pressure and temperature are the same

Step 2: Ideal gas law

The ideal gas law = p*V=nRT

For O2: p*2V = n(O2)*R*T

For CO2: p*V = n(CO2)*R*T

n(O2)*R*T / P*2V = n(CO2)*R*T / P*V

Since P, R and T are contstant, we can simplify this to:

n(O2)/2 = n(CO2)

Step 3: Calculate moles of O2

Moles O2 = mass O2/ Molar mass O2

Moles O2 = 41.6 grams / 32 g/mol

Moles O2 = 1.3 mol O2

The number of moles CO2 = 0.65 mol

Mass of CO2 = Moles CO2 * Molar Mass CO2

Mass of CO2 = 0.65 mol * 44.01 g/mol

Mass of CO2 = 28.6 grams

The mass of carbon dioxide is 28.6 grams

5 0

4 years ago

I am using all my points to ask this. please help

ELEN [110]

Answer:

C5H7N

C10H14N2

Explanation:

ok so lets lay out this nicely

elements C H N

percentage 74 8.7 17.3

mass number 12 1 14

divided percentage by mass 6.167 8.7 1.2357

now divide the smallest number with the 4.99 7.04 1

rest for instance 1,237 is the smallest.

so 6.167÷1,237

and 8.7 ÷1.237

and 1,237 divide 1.237

now the ratio is C5H7N

now for molecular formula find Mr of C5H7N which is (12×5)+7+14=81

next divide 162.1÷81=2

so now for molecular formula just multipily everythng by 2

C10H14N2

5 0

3 years ago

Calculate the molarity of sodium chloride in a half-normal saline solution (0.45% NaCl). The molar mass of NaCl is

Rus_ich [418]

Answer:

0.077 M

Explanation:

Data Given :

The concentration of half normal (NaCl) saline = 0.45g / 100 g

So,

Volume of Solution = 100 g = 100 mL

Volume of Solution in Liter = 100 mL / 1000

Volume of Solution = 0.1 L

molar mass of NaCl = 58.44 g/mol

Molarity:

Molarity is the representation of the solution. It is amount of solute in moles per liter of solution and represented by M

Formula used for Molarity

M = moles of solute / Liter of solution . . . . . . . . . . (1)

Now to find number of moles of Nacl

no. of moles of NaCl = mass of NaCl / molar mass

no. of moles of NaCl = 0.45g / 58.44 g/mol

no. of moles of NaCl = 0.0077 g

Put values in the eq (1)

M = moles of solute / Liter of solution . . . . . . . . . . (1)

M = 0.0077 g / 0.1 L

M = 0.077 M

So the molarity of half-normal saline solution (0.45% NaCl) = 0.077 M

3 0

3 years ago

How many liters of hydrogen gas is formed from the complete reaction of 15.2 g C? Assume that the hydrogen gas is collected at a

ira [324]

Answer:

38 L

Explanation:

There is some info missing. I think this is the original question.

Consider the chemical reaction: C(s) + H₂ O(g) ⟶ CO(g) + H₂ (g). How many liters of hydrogen gas is formed from the complete reaction of 15.2 g C? Assume that the hydrogen gas is collected at a pressure of 1.0 atm and a temperature of 360 K.

Step 1: Write the balanced equation

C(s) + H₂ O(g) ⟶ CO(g) + H₂ (g)

Step 2: Calculate the moles corresponding to 15.2 g of C

The molar mass of C is 12.01 g/mol.

$15.2g \times \frac{1mol}{12.01g} = 1.27 mol$

Step 3: Calculate the moles of H₂ produced from 1.27 moles of C

The molar ratio of H₂ to C is 1:1. The moles of H₂ produced are 1/1 × 1.27 mol = 1.27 mol.

Step 4: Calculate the volume of H₂

We will use the ideal gas equation.

$P \times V = n \times R \times T\\V = \frac{n \times R \times T}{P} = \frac{1.27mol \times \frac{0.0821atm.L}{mol.K} \times 360K}{1.0atm}= 38 L$

3 0

4 years ago

This answer is incorrect.

Alexxandr [17]

I believe the correct answer would be B because you can't make chromosomes

7 0

3 years ago