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ycow [4]
3 years ago
6

Choose all the problems that you will solve by regrouping. A. 65 – 56 = ? B. 28 – 15= ? C. 16 – 6 = ? D. 74 – 38 = ?

Mathematics
1 answer:
Vlada [557]3 years ago
7 0

Answer:

(a) and (d) will be done by regrouping

Step-by-step explanation:

Solution will be done by regrouping if unit term of term which is subtracted is greater then the term which subtracts.

(a) 65 -56, since the unit term of 65 is 5 and of 56 is 6

as the unit terms of 56 is greater than unit term of 65

Thus solution will be done by regrouping

⇒ 65 -56 = 9

(b) 28 -15, since the unit term of 28 is 8 and of 15 is 5

as the unit terms of 28 is greater than unit term of 15

Thus solution will not be done by regrouping

⇒ 28 -15 = 13

(c) 16 -6, since the unit term of 16 is 6 and of 6 is 6

as the unit terms of 16 is equal to unit term of 6

Thus solution will not be done by regrouping

⇒ 16 -6 = 10

(d) 74-38 , since the unit term of 74 is 4 and of 38 is 8

as the unit terms of 38 is greater than unit term of 74

Thus solution will be done by regrouping

⇒ 74-38 = 36

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blagie [28]

Answer:

26.95% probability that at least one of them is cleared with an arrest

Step-by-step explanation:

For each burglary, there are only two possible outcomes. Either it is cleared, or it is not. The probability of a burglary being cleared is independent of other burglaries. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

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This means that p = 0.051

A new detective is assigned to six different burglaries.

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Either none are cleared, or at least one is. The sum of the probabilities of these events is 100% = 1. So

P(X = 0) + P(X \geq 1) = 1

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In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{6,0}.(0.051)^{0}.(0.949)^{6} = 0.7305

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.7305 = 0.2695

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