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Elina [12.6K]
3 years ago
8

Identify the oxidizing agent and the reducing agent for 4Li(s) + O_2 (g) to 2Li_2O(s).

Chemistry
1 answer:
Doss [256]3 years ago
7 0
The reaction is:

<span>4Li(s) + O2 (g) = 2Li+  + 2O-2(s).

The oxidizing agent is the one that is being reduced which is oxygen  where the charge changed from neutral to -2 while the reducing agent is the on being oxidized which is lithium where the charge change from neutral to +1.</span>
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