Answer:
The answer to your question is: 52.92 g of CuNO₃
Explanation:
Data
grams of CuNO₃ = ?
volume = 1 l
concentration = 0.420 M
MW of CuNO₃ = 64 + 14 + 3(16) = 126 g
Formula
Molarity = moles / volume
moles = Molarity x volume
moles = 0.420 x 1
moles = 0.420 moles
1 mol of CuNO₃ ------------------- 126 g of CuNO₃
0.420 moles CuNO₃ ------------- x
x = (0.420 x 126) / 1
x = 52.92 g of CuNO₃
Find the moles of BaSO4 first. Then since we know it's a one to one ratio from barium chloride to barium sulfate we can just solve for liters.
<span>First you need to find the moles BaSO4 , and the you will require to find barium sulfate in liters.
</span>12.00gBaSO4 / 233.31 grams per mole
=.05141moles
Molarity=moles/liters
Hence,
Liters=.05141moles/.6Molarity
=.85 liters
Answer:
- The NaCl solution will have higher boiling point.
Explanation:
- C2H6O2 is a molecular substance. Meaning that when it dissolves it will remain this way:
C2H6O2 ---------> C6H12O6 (aq)
- Sodiumchloride (NaCl) is an ionic substance. Meaning that when it dissolves, it will create ions:
NaCl(s)-------> Na+(aq) + Cl- (aq)
Conclusion:
- NaCl is an ionic compound and C2H6O2 is a molecular compound. Ionic compounds have higher boiling points than molecular compounds. Therefore, NaCl will have the higher boiling point.