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3 years ago

What is true of tectonic plates?

Chemistry

1 answer:

kupik [55]3 years ago

3 0

Answer:

Plate tectonics is the theory that Earth's outer shell is divided into several plates that glide over the mantle, the rocky inner layer above the core. The plates act like a hard and rigid shell compared to Earth's mantle. ... The lithosphere includes the crust and outer part of the mantle.

Explanation:

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10.

Ugo [173]

Answer:

Density, $\rho=24.68\ g/cm^3$

Explanation:

Mass of a marble slab is 38.6 kg 38600 grams

The dimensions of the marble is 17 cm×23 cm×4 cm

We need to find its density. Mass per unit volume equals density. So,

$\rho=\dfrac{m}{V}\\\\\rho=\dfrac{m}{lbh}\\\\\rho=\dfrac{38600\ g}{(17\times 23\times 4)\ cm^3}\\\\\rho=24.68\ g/cm^3$

So, the density of the marble slab is $24.68\ g/cm^3$

5 0

4 years ago

Which of he following is a secondary alkanol?

hodyreva [135]

Answer: Thus $CH_3CH(OH)CH_3$ is a secondary alkanol.

Explanation:

Alkanol are compounds which contains carbons bonded by single bonds and contains hydroxy (-OH) as functional group.

Primary alkanol are those compounds which contain hydroxyl group attached a carbon which is further attached to a single carbon atom. Example: $CH_3CH_2CH_2OH$ and $CH_3CH_2CH_2CH_2OH$

Secondary alkanol are those compounds which contain hydroxyl group attached to a carbon which is further attached to two more carbon atoms.Example: $CH_3CH(OH)CH_3$

Tertiary alkanol are those compounds which contain hydroxyl group attached to a carbon which is further attached to three more carbon atoms. Example: $C(CH_3)_3OH$

Thus $CH_3CH(OH)CH_3$ is a secondary alkanol.

5 0

3 years ago

PLEASE HELP ASAP

swat32

Answer:

12.34 amu

Explanation:

Let the 1st isotope be A

Let the 2nd isotope be B

Let the 3rd isotope be C

From the question given above, the following data were obtained:

1st Isotope (A):

Mass of A = 12.32 amu

Abundance (A%) = 19.5%

2nd isotope (B):

Mass of B = 13.08 amu

Abundance (B%) = 26.23%

3rd isotope (C):

Mass of C = 11.99 amu

Abundance (C%) = 54.27%

Atomic mass of X =?

The atomic mass of the element X can be obtained as follow:

Atomic mass = [(Mass of A × A%)/100] + [(Mass of B × B%)/100] + [(Mass of C × C%)/100]

= [(12.32 × 19.5)/100] + [(13.08 × 26.23)/100] + [(11.99 × 54.27)/100]

= 2.402 + 3.431 + 6.507

= 12.34 amu

Thus, the atomic mass of the element X is 12.34 amu

7 0

3 years ago

What is the empirical formula?

Olenka [21]

Answer:

CH (92.2% C; 7.8% H), or just CH2

6 0

3 years ago

What types of chemical reactions are needed to make the perfect s'more?

iren [92.7K]

Answer:

sorry i never learned this

Explanation:

3 0

3 years ago