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3 years ago

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1 answer:

sweet-ann [11.9K]3 years ago

7 0

Answer:

The acid must be a concentrated acid

Explanation:

Ethene is prepared in the laboratory by heating ethanol with excess concentrated tetraoxosulphate VI acid at 170°C . The reactionoccursc in two stages;

1) when the ethanol and sulphuric acid are mixed in a ratio of 1:2, ethyl hydrogentetraoxosulpate VI is formed

2) The compound formed in the first step is heated in the presence of excess concentrated sulphuric acid to give ethene and sulphuric acid.

The overall reaction can be perceived as the dehydration of ethanol. The gas produced (ethene) is usually passed through sodium hydroxide solution to remove any gaseous impurities present.

concentrated sulphuric acid is used in this process since it is a good dehydrating agent.

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3 years ago

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The decomposition of N2O4 into NO2 has Kp = 2. Some N2O4 is placed into an empty container, and the partial pressure of NO2 at e

Sunny_sXe [5.5K]

Answer: Option (B) is the correct answer.

Explanation:

Expression for the given decomposition reaction is as follows.

$N_{2}O_{4} \rightarrow 2NO_{2}$

Let us assume that x concentration of $N_{2}O_{4}$ is present at the initial stage. Therefore, according to the ICE table,

$N_{2}O_{4} \rightarrow 2NO_{2}$

Initial : x 0

Change : - 0.1 $2 \times 0.1$

Equilibrium : (x - 0.1) 0.2

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Putting the given values into the above formula as follows.

$K_{p} = \frac{P^{2}_{NO_{2}}}{P_{N_{2}O_{4}}}$

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$2 \times (x - 0.1) = (0.2)^{2}$

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2 years ago

If the initial volume is 55ml and the final volume after some rocks of sandstone are added is 65ml what is the volume of the chi

AfilCa [17]

Answer:

Volume = 10ml

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Explanation:

The rocks are 10ml since the initial volume went up by 10.

Since density = mass/volume, you divide 2 by 10.

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2 years ago

A sample has a pH of -0.248 (yes, it really is possible to have a negative pH). Find

dalvyx [7]

Answer:

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pH+pOH= 14

pOH= 14-pH

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pOH= 14.248

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[OH-]=10^-pOH= 10^-14.248=5.65 x10^-15M

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