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3 years ago

Based on the balanced equation below, what is the mole ratio of HCl to VOC13?

Chemistry

1 answer:

Novay_Z [31]3 years ago

5 0

Answer:

6 HCl to 2 VOCl3

Explanation:

The coeffcients in front of the elements, represent moles. Therefore because the equation is balanced, you would evaluate your answer of the mole based off of what the question is asking. The question asked about the mole ratio of the two elements HCl to VOCL3. There is a number 6 in front of HCl which means that there are 6 moles of HCl, and there is a 2 in front of VOCL3 which means that there are 2 moles of VOCL3.

Therefore the correct answer will be 6 HCl to 2 VOCL3

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Consider the following reaction: 2CH3OH(g)  2CH4(g) + O2(g) ΔH = +252.8 kJ a) Calculate the amount of heat transferred when 24.

denpristay [2]

Answer:

For a: The amount of heat transferred for the given amount of methanol is 94.6736 kJ.

For b: The mass of methane gas produced will be 10.384 g.

Explanation:

For the given chemical reaction:

$2CH_3OH(g)\rightarrow 2CH_4(g)+O_2(g);\Delta H=+252.8kJ$

For a:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ......(1)

Given mass of methanol = 24.0 g

Molar mass of methanol = 32.04 g/mol

Putting values in above equation, we get:

$\text{Moles of methanol}=\frac{24.0g}{32.04g/mol}=0.749mol$

By Stoichiometry of the reaction:

For every 2 moles of methanol, the amount of heat transferred is +252.8 kJ.

So, for every 0.749 moles of methanol, the amount of heat transferred will be = $\frac{252.8}{2}\times 0.749=94.6736kJ$

Hence, the amount of heat transferred for the given amount of methanol is 94.6736 kJ.

For b:

By Stoichiometry of the reaction:

252.8 kJ of energy is absorbed when 2 moles of methane gas is produced.

So, 82.1 kJ of energy will be absorbed when = $\frac{2}{252.8}\times 82.1=0.649mol$ of methane gas is produced.

Now, calculating the mass of methane gas from equation 1, we get:

Molar mass of methane gas = 16 g/mol

Moles of methane gas = 0.649 moles

Putting values in equation 1, we get:

$0.649mol=\frac{\text{Mass of methane gas}}{16g/mol}\\\\\text{Mass of methane}=10.384g$

Hence, the mass of methane gas produced will be 10.384 g.

7 0

4 years ago

Lorek lives near the North Pole. The snow in his backyard adds water to the atomosphere through______.

Elis [28]

Hello :))

Your question was:Lorek lives near the North Pole. The snow in his backyard adds water to the atomosphere through______.
The answer is: Sublimation

Hope this helps!
Good day! :D

3 0

3 years ago

If an element has three isotopes with known natural abundance percentages, what other information is needed to find the average

Sati [7]

The average atomic mass of the element is the weighted average atomic mass of element with respect to the natural abundance of all the isotopes.
isotopes are atoms of the same elements with different mass numbers , in other words same number of protons but different numbers of neutrons.
to find the average atomic mass we need to know the atomic masses of all the isotopes in addition to the natural abundance percentages of the isotopes.

answer is we need to know the atomic masses of the isotopes as well

4 0

3 years ago

Read 2 more answers

QUICK PLEASE HELP!!!during a combustion reaction, 5.00 grams of oxygen reacted with 5.00 grams of CH4.

stealth61 [152]

The balanced chemical reaction is:

CH4 + 2O2 —> CO2 + 2H2O

You need to convert mass to moles (divide by molar mass):

CH4 moles = 5 / 16 = 0.31 mol
O2 moles = 5 / 32 = 0.16 mol

To figure out which reactant is limiting, divide the actual moles by the corresponding coefficient in the reaction:

CH4: 0.31 / 1 = 0.31
O2: 0.16 / 2 = 0.08

O2 is the lower number, so it is the limiting reactant. From the reaction we know it takes 2 moles of O2 to react with each mole of CH4. Therefore, for however many moles of O2 we actually have, half as many moles of CH4 will react. Since we have 0.16 mol of O2, only 0.08 mol of CH4 will react, leaving behind 0.31 - 0.08 = 0.23 mol of CH4.

Now convert back to mass (multiply by molar mass) to find the mass of CH4 remaining:

0.23 x 16 = 3.68g

The closest answer is B.

6 0

3 years ago

At what temperature can 10g of Cez(SO4)3 be dissolved in 100g of water?

dmitriy555 [2]

I would say the answer is a

7 0

3 years ago

Read 2 more answers