Answer:
See explanation
Explanation:
The formal charge is obtained from;
Formal Charge = Valence electrons on atom - [number of bonds - lone pair electrons]
The correct structure of ClF2+ is the structure attached to this answer (image obtained from quora) in which the formal charge on fluorine is zero and the formal charge on chlorine is + 1. This is the correct structure because the chlorine is more electronegative than fluorine as expected.
First, we will get the average pH of the two given values:
average pH = (6.4+8) / (2) = 7.2
At this average pH, the concentration of the acid from the phenol red is equal to the concentration of the base.
pH = 7.2
[H+] = 10^(-7.2) = 6.3 * 10^-8
Phenol red has the general formula HA, this gives us:
HA <.......> H+ + A-
At pH = 7.2, [H+] = [A-]
<span>Ka = [H+][A-]/ [HA]
</span>Ka = [H+] = <span>6.3 x 10^-8</span>
are hydrogen atoms which have lost protons
Answer:
A. The spectrum shows a single electron in the 2p subshell.
Explanation:
Answer:
![K_c\text{ = }\frac{[O_2][H_2]\placeholder{⬚}^2}{[H_2O]\placeholder{⬚}^2}](https://tex.z-dn.net/?f=K_c%5Ctext%7B%20%3D%20%7D%5Cfrac%7B%5BO_2%5D%5BH_2%5D%5Cplaceholder%7B%E2%AC%9A%7D%5E2%7D%7B%5BH_2O%5D%5Cplaceholder%7B%E2%AC%9A%7D%5E2%7D)
Explanation:
Here, we want to write the equilibrium constant expression
To write this, we raise the concentrations of the reactants and products to the coefficient before them. These concentrations are represented by square brackets in which the chemical formula of the compound is placed
We place the representation of the products over that of the reactants
We have the expression written as follows:
![K_c\text{ = }\frac{[H_2]\placeholder{⬚}^2[O_2]}{[H_2O]\placeholder{⬚}^2}](https://tex.z-dn.net/?f=K_c%5Ctext%7B%20%3D%20%20%7D%5Cfrac%7B%5BH_2%5D%5Cplaceholder%7B%E2%AC%9A%7D%5E2%5BO_2%5D%7D%7B%5BH_2O%5D%5Cplaceholder%7B%E2%AC%9A%7D%5E2%7D)
