Always. You never know what kind of chemical you’re dealing with and how powerful it is.
Answer:
Na2SO4 is equal to 0.0070401642780093 mole.
Explanation:
The electron bit would be 2 and you could colour in 4 boxes:) I had the same question as this and I got it correct
Actually, we can answer the problem even without the first statement. All we have to do is write the reaction for the production of sulfur trioxide.
2 S + 3 O₂ → 2 SO₃
The stoichiometric calculations is as follows:
6 g S * 1 mol/32.06 g S = 0.187 mol S
Moles O₂ needed = 0.187 mol S * 3 mol O₂/2 mol S = 0.2805 mol O₂
Since the molar mas of O₂ is 32 g/mol,
Mass of O₂ needed = 0.2805 mol O₂ * 32 g/mol = 8.976 g O₂
