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IgorC [24]
3 years ago
7

Reactioneaza total 22 kg calcar de puritate 80 % cu o solutie de acid clorhidric de concentratie 30 %. Stiind ca rezulta clorura

de calciu, apa si dioxid de carbon, se cer:
a. ecuatia reactiei chimice;
b. masa de solutie de acid clorhidric stoechiometric necesara;
c. masa de clorura de calciu rezultata;
d. cantitatea/numarul de moli de apa.
Chemistry
1 answer:
WINSTONCH [101]3 years ago
7 0

Answer:

De la Alex;)(da alex ăla de e din cls cu tn:)

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Which type of matter can be separated by physical means? A. atom B. element C. compound D. mixture
madreJ [45]

Answer:

b

Explanation:

A pure substance has a constant composition and cannot be separated into simpler substances by physical means. There are two types of pure substances: elements and compounds.

7 0
2 years ago
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A researcher recorder that a chemical reaction require 2.90 gal water and raised the temperature of the reaction vessel by 57°F.
Ivan

Answer:

10.875L

Explanation:

The problem here is a simple conversion. The conversion is from gal to liters Liter is a SI unit for recording volume as stated in the problem.

Given that:

              1 gallon of water = 3.75L

              2.90 gallon will be 2.9 x 3.75; 10.875L

4 0
3 years ago
If the initial volume is 55ml and the final volume after some rocks of sandstone are added is 65ml what is the volume of the chi
AfilCa [17]

Answer:

Volume = 10ml

Density = 1/5 g/ml or 0.20g/ml

Explanation:

The rocks are 10ml since the initial volume went up by 10.

Since density = mass/volume, you divide 2 by 10.

D = 2/10

D = 1/5 g/ml or 0.20g/ml

(Unit is g/ml aka grams/millileter)

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2 years ago
Xxxx only girls can join gca-vtki-tqh ​
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6 0
2 years ago
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If 72.5 grams of calcium metal (Ca) react with 65.0 grams of oxygen gas (O2) in a synthesis reaction, how many grams of the exce
Natali5045456 [20]
2Ca + O2 = 2CaO
First, determine which is the excess reactant
72.5 g Ca (1 mol) =1.8089725036
(40.078 g)

65 g O2 (1 mol) =2.0313769611
(15.999g × 2)
Since the ratio of to O2 is 2:1 in the balanced reaction, divide Ca's molar mass by 2 to get 0.9044862518. this isn't necessary because Ca is already obviously the limiting reactant. therefore, O2 is the excess reactant.

Now do the stoichiometry
72.5 g Ca (1 mol Ca) (1 mol O2)
(40.078 g Ca)(2 mol Ca)(31.998g O2)

=0.0282669621 g of O2 left over
5 0
3 years ago
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