The SI unit for volume is cubic meters of M^3
Answer:
30.12 g/m is the molar mass of the compound
Explanation:
Freezing point depression to solve this. The formula for the colligative property is:
ΔT = Kf . m
ΔT = T° freezing pure solvent - T° freezing solution
Kf = Cryoscopic constant
m = molality (mol/kg)
T° freezing pure benzene: 5.5°C
(5.5°C - 1.02°C) = 5.12 °C/m . m
4.48°C = 5.12 °C/m . m
4.48°C / 5.12 °C/m = m → 0.875 mol/kg
Mol = mass / molar mas
Molality = mol /kg
Let's find out the molar mass, with this equation:
(6.59 g / Molar mass) / 0.250 kg = 0.875 mol/kg
6.59 g / molar mass = 0.875 mol/kg . 0.250 kg
6.59 g / molar mass = 0.21875 mol
6.59 g / 0.21875 mol = molar mass → 30.12 g/m
Cul (s) --> represents its state which means solid, Here Valency of copper is 1 so its cuprous.
<span>Fe2O3--> Ferric Oxide is a solid. Here valency of Fe is +3 so its Ferric </span>
<span>CoF2--> Cobalt Flouride is a solid</span>
<span>FeO --> Ferrous Oxide is a solid. Here valency of iron is +2 so its Ferrous. </span>
4. If you evaporate the water first, then the sand and salt will be nearly impossible to separate. That eliminates 1 and 2. You can't filter salt out from an aqueous solution, so that eliminates 3. 4 works because you can filter out the sand (which doesn't dissolve) then evaporate the water away from the salt.
Answer: Options (a) and (d) are the correct answer.
Explanation:
A catalyst is the substance which helps in increasing the rate of reaction.
Activation energy is the minimum amount of energy required by reactants to start the reaction. On addition of catalyst, the path of reaction changes because the energy barrier gap reduces and hence, the activation energy also decreases.
In the absence of catalyst, we need to increase the temperature so that reaction can occur quickly.
Whereas on addition of catalyst, there is no need to increase the temperature as the catalyst itself is sufficient to increase the rate of reaction. As a result, temperature should be lowered when there is addition of catalyst in the reaction.
Thus, we can conclude that catalysts can save money by essentially lowering the activation energy and temperature required.
