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barxatty [35]
3 years ago
14

Which of the following is not a property of most transition metals?

Chemistry
2 answers:
irakobra [83]3 years ago
7 0

Answer:

Low melting point

Explanation:

Most transition metals property is high melting point.

saul85 [17]3 years ago
3 0

Answer:

Low melting point

Explanation:

Transition metals have the following properties:

Conductivity (Electrical and Thermal)

Malleability (You can hit it with a hammer to mold it)

High melting point

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Answer:

Initial volume: mL

Final volume: mL

Volume of rock: cm3

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3 years ago
Which of the following chemical formulas contains the most molecules?
maw [93]
C. 2Fe2O3 would be the correct answer!
4 0
3 years ago
At 850 K, the equilibrium constant for the reaction
Sphinxa [80]

Answer:

Answers are in the explanation.

Explanation:

<em>Given concentrations are:</em>

  • <em>SO₂ = 0.20M O₂ = 0.60M SO₃ = 0.60M</em>
  • <em>SO₂ = 0.14M O₂ = 0.10M SO₃ = 0.40M </em>
  • <em>And SO₂ = 0.90M O₂ = 0.50M SO₃ = 0.10M</em>

<em />

In the reaction:

2SO₂(g) + O₂(g) ⇄ 2SO₃(g)

Kc is defined as:

Kc = 15 = [SO₃]² / [O₂] [SO₂]²

<em>Where concentrations of each species are equilbrium concentrations.</em>

<em />

Also, you can define Q (Reaction quotient) as:

Q = [SO₃]² / [O₂] [SO₂]²

<em>Where concentrations of each species are ACTUAL concentrations.</em>

<em />

If Q > Kc, the reaction will shift to the left until Q = Kc;

If Q < Kc, the reaction will shift to the right until Q = Kc

If Q = Kc, there is no net reaction because reaction would be en equilibrium.

Replacing with given concentrations:

  • Q = [0.60M]² / [0.60M] [0.20M]² = 15; Q = Kc → No net reaction
  • Q = [0.40M]² / [0.10M] [0.14M]² = 82; Q > Kc, → Reaction will shift to the left
  • Q = [0.10M]² / [0.50M] [0.90M]² = 0.015; Q < Kc → Reaction will shift to the right

<em />

8 0
3 years ago
Is 6.0 × 10 to the negative 4th power is a significant figure?​
Dmitry_Shevchenko [17]

Answer:

Yes

Explanation:

First remember that a significant figure are basically values that contribute to the precision of a value. In any scientific notation the values are significant figures because these values stay the same. In this case we have two significant figures which is 6 and 0, you can further prove that they are significant figures by converting the notation into standard form.

6.0\times10^{-4}

Negative so move the decimal point to the left:

=0.00060

6 and 0 are the significant figures in this standard notation because it's precise to it's actual value which is 6.0.

To sum up, the values you have on the left side of a notation are significant figures since they will not change no matter if it's standard or scientific notation meaning it's precise.

Hope this helps.

6 0
2 years ago
Which would be isotopes?
otez555 [7]

Answer:

e

Explanation:

8 0
3 years ago
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