Answer:
(40 g O) / (15.99943 g O/mol) x (1 mol CaCO3 / 3 mol O) x (100.0875 g CaCO3/mol) =
83 g CaCO3
So answer D), although three significant digits are not justified.
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2.
The reason why is because there are 2 available electron spots on the orbital for the oxygen atom. Hydrogen atoms have one proton and one electron, thus, in order to fill the oxygen atom orbital to a full outer shell, a maximum of 2 atoms could bond with the oxygen atoms.
6 electrons (oxygen)+ 1 electron (hydrogen)+ 1 electron (hydrogen)= 8
Answer:
78.85
Explanation:
To <u>calculate the average atomic mass of the isotopes </u>we use the <em>given masses and abundances</em>, as follows:
- Mass of Isotope 1 * Abundance of Isotope 1 + Mass of Isotope 2 * Abundance of Isotope 2 + ....
In other words:
- 78 amu * 75/100 + 81 amu * 15/100 + 82 amu * 10/100 = 78.85
So the answer is 78.85.
Answer:
B. Hydrogen and oxygen molecules
General Formulas and Concepts:
<u>Chemistry - Reactions</u>
- Reactants are always on the left side of the arrow
- Products are always on the right side of the arrow
Explanation:
<u>Step 1: Define</u>
Reaction RxN: 2H₂ + O₂ → 2H₂O
<u>Step 2: Identify</u>
Reactants: H₂ and O₂
Products: H₂O
