Answer:
Left or up, either one of those
Explanation:
Answer:
On the periodic table, electronegativity generally increases as you move from left to right across a period and decreases as you move down a group. As a result, the most electronegative elements are found on the top right of the periodic table, while the least electronegative elements are found on the bottom left.
Explanation:
Make sure to edit so you don't get copy-writed.
Answer:
A = 1,13x10¹⁰
Ea = 16,7 kJ/mol
Explanation:
Using Arrhenius law:
ln k = -Ea/R × 1/T + ln(A)
You can graph ln rate constant in x vs 1/T in y to obtain slope: -Ea/R and intercept is ln(A).
Using the values you will obtain:
y = -2006,9 x +23,147
As R = 8,314472x10⁻³ kJ/molK:
-Ea/8,314472x10⁻³ kJ/molK = -2006,9 K⁻¹
<em>Ea = 16,7 kJ/mol</em>
Pre-exponential factor is:
ln A = 23,147
A = e^23,147
<em>A = 1,13x10¹⁰</em>
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I hope it helps!
<u>Answer:</u> The initial concentration of hydrogen peroxide at the given temperature is 0.399 M
<u>Explanation:</u>
Decomposition of hydrogen peroxide is following first order kinetics.
Rate law expression for first order kinetics is given by the equation:
![k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}](https://tex.z-dn.net/?f=k%3D%5Cfrac%7B2.303%7D%7Bt%7D%5Clog%5Cfrac%7B%5BA_o%5D%7D%7B%5BA%5D%7D)
where,
k = rate constant = 
t = time taken for decay process = 855 s
= initial amount of the reactant = ?
[A] = amount left after decay process = 0.321 M
Putting values in above equation, we get:
![2.54\times 10^{-4}s^{-1}=\frac{2.303}{855s}\log \frac{[A_o]}{0.321}](https://tex.z-dn.net/?f=2.54%5Ctimes%2010%5E%7B-4%7Ds%5E%7B-1%7D%3D%5Cfrac%7B2.303%7D%7B855s%7D%5Clog%20%5Cfrac%7B%5BA_o%5D%7D%7B0.321%7D)
![[A_o]=0.399M](https://tex.z-dn.net/?f=%5BA_o%5D%3D0.399M)
Hence, the initial concentration of hydrogen peroxide at the given temperature is 0.399 M