Answer:
a) [H₃O⁺] = 1.8x10⁻⁵ M
b) pH = 4.75
c) % rxn = 3.5x10⁻³ %
Explanation:
a) The dissociation reaction of HCN is:
HCN(aq) + H₂O(l) ⇄ H₃O⁺(aq) + CN⁻(aq)
0.5 M - x x x
The dissociation constant from the above reactions is given by:


By solving the above quadratic equation we have:
x = 1.75x10⁻⁵ M = 1.8x10⁻⁵ M = [H₃O⁺] = [CN⁻]
Hence, the [H₃O⁺] is 1.8x10⁻⁵ M.
b) The pH is equal to:
Then, the pH of the HCN solution is 4.75.
c) The % reaction is the % ionization:

Therefore, the % reaction or % ionization is 3.5x10⁻³ %.
I hope it helps you!
Chlorophyll, it is chlorophyll
<span>[Ar]4s²3d¹⁰4p⁴
We see that the last level is this element is 4, so this element should be in
4th period, it has 4 p-electrons, so it should be in 16th group.
4th period, 16th group - it is Se.
You can also go to the next element after Ar, and count beginning of this element 16. (2+10+4 =16 electrons)
From "K" (where K is the first) you count to 16 and it is going to be Se.</span>
Iron oxide!!!!!!!!!!!!!!!!!!!!