It is a presumptive test for cocaine.
Answer:
true
Explanation:
light travels faster than sound.
Answer:
3.35 atm
Since P₂ > 3.00 atm, the lighter would explode.
Explanation:
Step 1: Given data
- Initial pressure of butane gas (P₁): 2.50 atm
- Initial temperature of butane gas (T₁): 293 K
- Final pressure of butane gas (P₂): ?
- Final temperature of butane gas (T₂): 393 K
Step 2: Calculate the final pressure of butane gas
If we assume ideal behavior, we can calculate the final pressure of butane gas using Gay Lussac's law.
P₁/T₁ = P₂/T₂
P₂ = P₁ × T₂/T₁
P₂ = 2.50 atm × 393 K/293 K = 3.35 atm
Since P₂ > 3.00 atm, the lighter would explode.
When the balanced reaction equation of methane combustion is:
CH4 + 2O2 →CO2 + 2H2O
so, we can see that each 1 mole of methane combusted will give 2 moles of water as a product.
so first, we need to get the moles of methane =
= mass of methane /molar mass of methane
= 52.6 g / 16.04 g/mol
= 3.28 moles
when 1 mol of methane produces→ 2 moles of water
∴ 3.28 moles methane produces → X moles of water
∴ moles of water = 3.28 * 2
= 6.56 moles
when each 1 mole of water has 6.02 x 10^23 (Avogadro's number ) individual molecules:
∴number of molecules of water = 6.56 * 6.02 x 10^23
= 3.9 x 10^24 molecules
Answer:what are u asking to do?
Explanation:
