Question

(b) What is the pH of 0.40 M triethylammonium chloride, CH₃ (CH₂)₃ NHCl ?

Answer 1

pH of 0.40M triethylammonium chloride is 5.90.

What is pH?

A solution's acidity may be determined by looking at its pH, which is a measurement of hydrogen ion concentration. Pure water slightly separates into ions with roughly equal amounts of hydrogen and hydroxyl (OH) ions. [H+] is 107 for a neutral solution, or pH = 7.

Given :

Concentration of triethylammonium chloride = 0.40M

pH = ?

Solution:

(CH3CH2)3NHCl ------> (CH3CH2)3NH⁺ + Cl⁻

(CH3CH2)3NH⁺ will react with water to give H3O⁺ .

(CH3CH2)3N will have a Kb = 5.2 x 10 ^(-4)

Kw = Kb x Ka

=> Ka = Kw / Kb = 10^(-14) / 5.2 x 10 ^(-4)

=> Ka = 1.92 x 10^(-11)

so by the reaction we have ,

Ka = x²/(0.40 - x)

=> x = 1.2393 x 10 ^(-6)

now, pH = -log( [H3O⁺]) = - log ( 1.2393 x 10 ^(-6)) = 5.906

To learn more about pH :

brainly.com/question/15289741

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