Mole ratio:
<span> MgCl</span>₂<span> + 2 KOH = Mg(OH)</span>₂<span> + 2 KCl
</span>
1 mole MgCl₂ -------------- 1 mole Mg(OH)₂
Answer B
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Answer:

Explanation:
To convert from representative particles to moles, Avogadro's Number: 6.02*10²³, which tells us the number of particles (atoms, molecules, etc.) in 1 mole of a substance.
We can use it in a ratio.

Multiply by the given number of molecules.

Flip the ratio so the molecules of water cancel out.



Divide.

The original number of molecules has 2 significant figures: 3 and 1, so our answer must have the same. For the number we calculated, that is the tenth place. The 4 in the hundredth place tells us to leave the 1.

There are about 5.1 moles of water in 3.1*10²⁴ molecules of water.
Answer: The orange color remains unchanged. (B)
Explanation:
Explanation:
The chemical reaction given in the question is as follows -
MnO₄⁻ (aq) + 8H⁺ (aq) + 5e⁻ → Mn²⁺ (aq) + 4H₂O (l)
NO₃⁻ (aq) + 4H⁺ (aq) + 3e⁻ → NO (g) + 2H₂O (l)
As we know , the value for reduction potential are -
Mn²⁺ = + 1.51 V
NO₃⁻ = +0.96 V
From , the data given above , the value of the reduction potential of NO₃⁻ is less than the reduction potential of Mn²⁺ .
Hence ,
NO₃⁻ can not oxidize Mn²⁺ .