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prisoha [69]
4 years ago
8

A sample of carbon-12 has a mass of 6.00 g. How many atoms of carbon-12 are in the sample?

Chemistry
2 answers:
kirill [66]4 years ago
7 0

Answer:

In short the answer is A, or 3.01 × 10^23

Vesna [10]4 years ago
3 0
Convert grams to moles [grams/molar mass] ~ Moles
Convert moles to atoms [moles * 6.02 x 10^23] = Atoms
Half of 6.02 x 10^23 is 3.01 x 10^23 so here is our answer.
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Which statement describes what it means for energy to be conserved?
ch4aika [34]

Answer:

energy released by a reaction is gained by the surroundings.

Explanation:

umm... I'm not 100% sure about this

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Why are basic radicals classified into six groups?​
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Basic radicals (cations) have been divided into groups based on Ksp values

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Some people are so good at their professions that other companies will try to recruit them?
Stella [2.4K]
Because they are good at their professions
7 0
3 years ago
What is the halogen in period 5?? it has six letters
Misha Larkins [42]
Simple,

take a look at your periodic table, if you have it labeled look at the Halogen

Group, it includes: Flourine, Chlorine, Bromine, Iodine, and Astatine.

Now, a period on the periodic table is read from left to right, and goes

down the rows of the periodic table.

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Iodine.

Thus, your answer.
8 0
3 years ago
A 1.0 mole sample of fluorine gas at 25 °C has an average molecular velocity of 415 m/s. What is the total KE of the gas sample?
Mariana [72]

The total kinetic energy of the gas sample is 3.3 KJ

<h3>What is kinetic energy? </h3>

This is the energy possessed by an object in motion. Mathematically, it can be expressed as:

KE = ½mv²

Where

  • KE is the kinetic energy
  • m is the mass
  • v is the velocity

<h3>How to determine the mass of the fluorine gas</h3>
  • Molar mass of fluorine gas = 38 g/mol
  • Mole of fluorine gas = 1 mole
  • Mass of fluorine gas = ?

Mass = mole × molar mass

Mass of fluorine gas = 1 × 38

Mass of fluorine gas = 38 g

<h3>How to determine the KE of the gas sample</h3>
  • Mass (m) = 38 g = 38 / 1000 = 0.038 Kg
  • Velocity (v) = 415 m/s
  • Kinetic energy (KE) =?

KE = ½mv²

KE = ½ × 0.038 × 415²

KE = 3272.275 J

Divide by 1000 to express in kilojoule

KE = 3272.275 / 1000

KE = 3.3 KJ

Learn more about energy:

brainly.com/question/10703928

#SPJ1

4 0
2 years ago
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