If Kendra started working at 10:30 a.m.and left at 6:15, how many hours of work should she record for the day on her time card

Mathematics

1 answer:

valina [46]3 years ago

7 0

(6+15/60)+12-(10+30/60)

6.25+12-10.5

7.75 hrs

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-5|4y-11|-3=12<br> Please answer with the steps

iren [92.7K]

-5║4y-11║-3=12
-5║4y-11║-3 +3=12+3
- 5║4y-11║=15
-5/5║4y-11║=15/-5
║4y-11║=-3

4y-11=-3 -5║4y-11║-3=12
4y-11+11=-3+11 -5║4(2)-11║-3=12
4y=8 -5║-3║-3=12
4y/4=8/4 -5 (3)-3=12
y=2 -18≠12

4y-11=3 -5║4y-11║-3=12
4y-11+11=3+11 -5║4(7/2)-11║-3=12
4y=14 -5(3)-3=12
4y/4=14/4 -18≠ 12
y=7/2

No solutions

3 0

3 years ago

Pls helps neds answer

Alik [6]

Helps on what?
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6 0

3 years ago

It takes an experienced groundskeeper 390 minutes to

sveta [45]

Answer: 223.77 minutes

Step-by-step explanation:

For this exercise you need to use the following formula:

$\frac{t}{t_A}+\frac{t}{t_B}=1$

Where $t_A$ is the individual time for object A, $t_B$ is the individual time for object B and $t$ is the time for A and B working together.

In this case, analizing the information given in the exercise, you can identify that:

$t_A=390\\\\t_B=525$

Knowing these values you can substitute them into the formula and then you must solve for "t" in order to calculate how long will it take working together.

You get that this is:

$\frac{t}{390}+\frac{t}{525}=1\\\\\frac{61}{13650} t=1\\\\61t=(1)(13650)\\\\t=\frac{13650}{61}\\\\t=223.77\ minutes$