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Ulleksa [173]
3 years ago
11

If Kendra started working at 10:30 a.m.and left at 6:15, how many hours of work should she record for the day on her time card

Mathematics
1 answer:
valina [46]3 years ago
7 0
(6+15/60)+12-(10+30/60)

6.25+12-10.5

7.75 hrs




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Answer:

y=-6

Step-by-step explanation:

y+6=0(x-5)

Solve

y=-6

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The soccer team and the American football team are sharing the field for practice today. The soccer team has practice every 2 da
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I believe the answer would be 4 days.

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If the area of a rectangle is 162 square meters, what is the length of the base
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Answer:

If the long side is down then the length of the base is 81 sq.m.

If the short side is down then the length of the base is 20.25 sq.m.

Step-by-step explanation:

162/4 is 40.5 that means if this were a square it would be 40.5 sq.m. On each side, if the base is longer you multiply 40.5 by 2 (or whatever youre supposed to honestl) and if the base is shorter you divide by 2 (or whatever you were supposed to)

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g If the economy improves, a certain stock stock will have a return of 23.4 percent. If the economy declines, the stock will hav
dusya [7]

Answer:

E(X) = 23.4* 0.67 -11.9*0.33= 11.759 \%

Now we can find the second central moment with this formula:

E(X^2) = \sum_{i=1}^n X^2_i P(X_i)

And replacing we got:

E(X^2) = (23.4)^2* 0.67 +(-11.9)^2*0.33= 413.5965

And the variance is given by:

Var(X) = E(X^2) - [E(X)]^2

And replacing we got:

Var(X) = 413.5965 -(11.759)^2 =275.5105

And finally the deviation would be:

Sd(X) = \sqrt{275.5105}= 16.599 \%

Step-by-step explanation:

We can define the random variable of interest X as the return from a stock and we know the following conditions:

X_1 = 23.4 , P(X_1) =0.67 represent the result if the economy improves

X_2 = -11.9 , P(X_1) =0.33 represent the result if we have a recession

We want to find the standard deviation for the returns on the stock. We need to begin finding the mean with this formula:

E(X) = \sum_{i=1}^n X_i P(X_i)

And replacing the data given we got:

E(X) = 23.4* 0.67 -11.9*0.33= 11.759 \%

Now we can find the second central moment with this formula:

E(X^2) = \sum_{i=1}^n X^2_i P(X_i)

And replacing we got:

E(X^2) = (23.4)^2* 0.67 +(-11.9)^2*0.33= 413.5965

And the variance is given by:

Var(X) = E(X^2) - [E(X)]^2

And replacing we got:

Var(X) = 413.5965 -(11.759)^2 =275.5105

And finally the deviation would be:

Sd(X) = \sqrt{275.5105}= 16.599 \%

7 0
3 years ago
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