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Savatey [412]
3 years ago
14

I need help with this pls

Chemistry
1 answer:
N76 [4]3 years ago
3 0

Answer:

1)20 \\ 2)13 \\ 3)82 \\ 4)56 \\ 5)26 \\ 6)1 \\ hope \: it \: helps \\ plzzz \: mark \: it \: as \: brainliest...

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Where is most of the water on earth found? What percentage?
bezimeni [28]

Answer:

The ocean holds about 97 percent of the Earth's water; the remaining three percent is found in glaciers and ice, below the ground, in rivers and lakes. Of the world's total water supply of about 332 million cubic miles of water, about 97 percent is found in the ocean.

wait..if you asking about the country it's Brazil✌️

8 0
2 years ago
EXPLAIN How would you explain the difference between single displacement and
IrinaK [193]
  • The difference between single displacement reaction and double displacement reaction are:

Explanation:

in the chemical reaction an atom in a molecule is replaced by another atom forming the end product .this type of chemical reaction involved only two reactants for example zinc + copper sulphate give us copper sulphate + copper.double displacement reaction is the reaction in which two compounds react together to form two other compounds by mutual exchange of other ions is called double displacement reaction.this type of reaction is involved two or more than two reactants.for example AG and O3 + NaCl give us agcl + nano3

3 0
2 years ago
I need help with #4... Chemistry is my worst subject.
ella [17]
Use slader.com it helps with all textbook work!
5 0
3 years ago
In a spacecraft tge carbon dioxide exhaled by the astronaut can be removed by the reaction with lithium hydroxide, LiOH accordin
quester [9]

Answer:

30 moles

Explanation:

From the equation it is a one - to - one reaction

3 0
2 years ago
Determine the AMOUNT OF NO2, LIMITING REACTANT, AND THE AMOUNT AND NAME OF EXCESS REACTANT.
zepelin [54]

Answer:

balanced equation mole ratio 5 2 mol NO/1 mol O2

10.00 g O2 3 1 mol O2/32.00 g O2 5 0.3125 mol O2

20.00 g NO 3 1 mol NO/30.01 g NO 5 0.6664 mol NO

actual mole ratio 5 0.6664 mol NO/0.3125 mol O2 5 2.132 mol NO/1.000 mol O2

Because the actual mole ratio of NO:O2 is larger than the balanced equation mole

ratio of NO:O2, there is an excess of NO; O2 is the limiting reactant.

Mass of NO used 5 0.3125 mol O2 3 2 mol NO/1 mol O2 5 0.6250 mol NO

0.6250 mol NO 3 30.01 g NO/1 mol NO 5 18.76 g NO

Mass of NO2 produced 5 0.6250 mol NO2 3 46.01 g NO2/1 mol NO2 5 28.76 g NO2

Excess NO 5 20.00 g NO 2 18.76 g NO 5 1.24 g N

Explanation:

3 0
2 years ago
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