an unknown volume of gas has a pressure of 0.50 atm and temperature of 325k. if the pressure is raised to 1.2atm and the tempera
ture decreased to 320k giving a new volume of 48L what was the initial volume
1 answer:
117 L. You can start by making a table to organize the information you are given. Then, you can use the formula PV/T=PV/T and plug in the numbers you have. You then solve for the missing volume. Remember that the initial pressure, temperature, and volume should be on one side of the equal sign, and the final pressure, volume, and temperature should be on the other side.
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Explanation:
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Answer:
Explanation:
In the chlorination of alkanes, the condition necessary is UV light so free radical substitution can take place. For alkanes like pentane, the primary, secondary and tertiary Hydrogen atoms (Hydrogen atoms bonded to their respective carbon) þare taken into consideration and this is because the tertiary Hydrogen is the most reactive (due to bond dissociation energy) hence the easiest to be substituted. The trend is as follows in the order of their reactivity;
1° < 2° < 3°
So, the products of the chlorination of pentane, the principal monochloride constituted is 3 - chloropentane while the other two monomers are:
2- chloropentane
1- chloropentane
Below is the attachment showing the structural formula of the three monochloride constituted pentane.
