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Rama09 [41]
3 years ago
11

an unknown volume of gas has a pressure of 0.50 atm and temperature of 325k. if the pressure is raised to 1.2atm and the tempera

ture decreased to 320k giving a new volume of 48L what was the initial volume

Chemistry
1 answer:
postnew [5]3 years ago
6 0
117 L. You can start by making a table to organize the information you are given. Then, you can use the formula PV/T=PV/T and plug in the numbers you have. You then solve for the missing volume. Remember that the initial pressure, temperature, and volume should be on one side of the equal sign, and the final pressure, volume, and temperature should be on the other side.

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I need a good picture of the ph scale with acids and bases including all the foods that go on it
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3 0
4 years ago
Which of the following is NOT correct about elements?
Lynna [10]

Answer: B. Elements are represented by chemical formulas.

Elements are pure substances, which means that they cannot be broken down into simpler substances. The element is the most basic substance that exists, breaking it down further means breaking it down into protons, neutrons, and electrons, which is no longer a substance.

Elements have chemical properties that allow them to form different types of bonds with other elements.

However, elements *alone* are not represented by their chemical formulas. Only chemical bonds or ions are represented by a chemical formula.

3 0
4 years ago
Read 2 more answers
Select the correct answer.
Lera25 [3.4K]

Answer:

1s^{2}2s^{2}2p^{6}3s^{2}3p^{4}

Explanation:

S is in 3d period, so it has 3 levels

1 level has 2 electrons, 2d level 8 electrons, 3d level 6 electrons

1s^{2}2s^{2}2p^{6}3s^{2}3p^{4}

3 0
4 years ago
Help plz:)))I’ll mark u Brainliest
emmasim [6.3K]

Answer:

\Delta _{fus}H=205J/g=13.03kJ/mol

Explanation:

Hello there!

In this case, since the heat of fusion is a property that allows us to calculate the heat involved during the change from solid to liquid (fusion) and is calculated as shown below:

Q=m*\Delta _{fus}H

In such a way, given the heat involved during this process and the mass of copper, we calculate the heat of fusion as shown below:

\Delta _{fus}H=\frac{Q}{m}=\frac{41000J}{200.g}\\\\\Delta _{fus}H=205J/g

Or in kJ/mol:

\Delta _{fus}H=205\frac{J}{gCu}*\frac{63.546 gCu}{1molCu}\\\\  \Delta _{fus}H=13026.93J/mol=13.03kJ/mol

Regards!

8 0
3 years ago
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