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seropon [69]
3 years ago
15

A car going 30 m/s to 70 m/s in 10 seconds calculate the acceleration of the car

Physics
2 answers:
Zina [86]3 years ago
7 0

70m/s-30m/s is eqal to 40m/s. Divide 40 by 10 and you get 4. This would be the accleration of the car.

Anastasy [175]3 years ago
6 0

4 should be the answer for the acceleration for the car. I hope this helps!

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PHYSICS
quester [9]

Answer:

c) 8.3 x 10^24 molecules

Explanation:

First of all, we convert the volume of the glass of water from mL to cm^3:

V=250 mL = 250 cm^3

The relationship between mass and volume is:

d=\frac{M}{V}

where

d=1.00 g/cm^3 is the density of water

M is the total mass of the glass of water

V=250 cm^3 is the volume of the water in the glass

Solving for M,

M=dV=(1.00)(250)=250 g = 0.250 kg

Now we know that the mass of a single molecule of water is

m=3.0\cdot 10^{-26}kg

The total mass of the water in the glass can be written as

M=Nm

where

N is the number of molecules in the glass of water

Solving for N, we find:

N=\frac{M}{m}=\frac{0.250}{3.0\cdot 10^{-26}}=8.3\cdot 10^{24}

7 0
3 years ago
What is the frequency of a radio wave with an energy of 3.686 × 10−24 j/photon?answer in units of hz?
Makovka662 [10]

To solve this problem, we have to use the formula:

E = h f

where E is total energy, h is Plancks constant 6.626x10^-34 J s, f is frequency

 

f = E / h

f = 3.686 × 10−24 J / (6.626x10^-34 J s)

<span>f = 5.56 x 10^9 Hz</span>

4 0
3 years ago
Which factor is least likely to limit the rate of photosynthesis?
madreJ [45]

Answer:

oxygen concentration

Explanation:

8 0
3 years ago
A race car traveling at 10 meters per second accelerates at 1.5 meters per second squared while moving a distance of 600 meters.
Mekhanik [1.2K]

Answer:

Explanation:

Givens

vi = 10 m/s

a = 1.5 m/s^2

d = 600 m

vf = ?

Formula

vf^2 = vi^2 + 2*a*d

Solution

vf^2 = 10^2 + 2*1.5 * 600

vf^2 = 100 + 1800

vf^2 = 1900

sqrt(vf^2) = sqrt(1900)

vf = 43.59 m/s

7 0
3 years ago
An elevator car weighs 5500 N. If the car accelerates upwards at a rate of 4.0 m/s2, what is the tension in the support cable li
nadya68 [22]

Answer:

Explanation:

The equation for this, since we are talking about weight on an elevator, is Newton's 2nd Law adjusted to fit our needs:

F_n=ma+w where the Normal Force needed to lift that elevator car is the tension. So the equation then becomes

T = ma + w where T is the tension in the cable to lift the elevator, m is the mass of the elevator (which we have to solve for), a is the acceleration of the elevator (positive since it's going up), and w is the weight of the elevator (which we have as 5500 N). Solving first for mass:

w = mg and

5500 =- m(10) so

m = 550 kg. Now we have what we need to solve for the tension:

T = 550(4.0) + 5500 and

T = 2200 + 5500 so

T = 7700 N

4 0
3 years ago
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