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seropon [69]
3 years ago
15

A car going 30 m/s to 70 m/s in 10 seconds calculate the acceleration of the car

Physics
2 answers:
Zina [86]3 years ago
7 0

70m/s-30m/s is eqal to 40m/s. Divide 40 by 10 and you get 4. This would be the accleration of the car.

Anastasy [175]3 years ago
6 0

4 should be the answer for the acceleration for the car. I hope this helps!

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on a distant planet a freely falling object has an acceleration of 20 m/s.^2 what speed will a body dropped from rest on his pla
N76 [4]

Answer:

30 m/s

Explanation:

Vf = ?

Vi = 0 m/s

a = 20 m/s^2

t = 1.5 s

Plug those values into the equation: Vf = Vi + at

Vf = 0 + (20)(1.5)

Vf = 30 m/s

4 0
3 years ago
The photons of different light waves:
LuckyWell [14K]

Answer: contain different amounts of energy

Explanation:

The energy E of a photon is given by:

E=h\nu

Where:

h=6.626(10)^{-34}\frac{m^{2}kg}{s} is the Planck constant

\nu is the frequency of the light which is inversely related to the wavelength.

Now, if we have photons of different light waves, this means we have photons with different frequencies.

As the energy of the photon depends on its frequency:

Photons of different light waves <u>contain different amounts of energy.</u>

8 0
3 years ago
A bicyclist starts at rest and speeds up to 30 m/s while accelerating at 4 m/s^2. Determine the distance traveled.
raketka [301]

Answer:

Distance, d = 112.5 meters

Explanation:

Initially, the bicyclist is at rest, u = 0

Final speed of the bicyclist, v = 30 m/s

Acceleration of the bicycle, a=4\ m/s^2

Let s is the distance travelled by the bicyclist. The third equation of motion is given as :

v^2-u^2=2as

s=\dfrac{v^2-u^2}{2a}

s=\dfrac{(30)^2}{2\times 4}

s = 112.5 meters

So, the distance travelled by the bicyclist is 112.5 meters. Hence, this is the required solution.

6 0
2 years ago
A helium atom (mass 4.0 u) moving at 598 m/s to the right collides with an oxygen molecule (mass 32 u) moving in the same direct
labwork [276]

Answer:

Speed of the helium after collision = 246 m/s

Explanation:

Given that

Mass of helium ,m₁ = 4 u

u₁=598 m/s

Mass of oxygen ,m₂ = 32 u

u₂  = 401 m/s

v₂ =445 m/s

Given that initially both are moving in the same direction and lets take they are moving in the right direction.

Speed of the helium after collision = v₁

There is no any external force on the masses that is why the linear momentum will be conserve.

Initial linear momentum = Final linear momentum

P = m v

m₁u₁+m₂u₂ = m₁v₁+m₂v₂

598 x 4 + 32 x 401 = 4 x v₁+ 32 x 445

v₁ = 246 m/s

Speed of the helium after collision = 246 m/s

6 0
3 years ago
A. How will the Milky Way continue to move outward as a result of the Big Bang?
emmasim [6.3K]

Answer:

i believe it is c

Explanation:

4 0
3 years ago
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