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Pepsi [2]
3 years ago
15

The four principle surveying methods to spatially determine the position of features are: Select one: ut of a. triangulation, tr

aversing, radiation, perpendicular offset b. triangulation, trilateration, radiation, traversing stion C. triangulation, trilateration, radiation, perpendicular offset d. theodolite and pacing, total station, compass and steel tape, Global navigation systems X e. traversing, trilateration, radiation, perpendicular offset
Physics
1 answer:
Natalija [7]3 years ago
7 0

A: perpendicular offset

B: radiation

C: transliteration

D: theodolite

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Why are some fasteners double or triple threaded?
OLga [1]
<span>Fasteners are double or triple threaded with the idea of durability. People look for durability in a fastener and if they receive one with triple threaded or double threaded they will feel more safe and at ease knowing it has extra strength added.</span>
3 0
3 years ago
Label the producers and consumers, then label the different types of consumers.
sdas [7]
The base of the pyramid has the producers and everything else above the base falls under the consumers category i.e the locusts,frogs and the snake. The grass is the producer, the locust is a consumer, the frog is a special type of omnivore, termed the "life-history omnivore" since they eat both plants and animals but at different times in their lives. In this case they are just omnivores and lastly, the snake is a carnivore.
3 0
3 years ago
Suppose you have two solid bars, both with square cross-sections of 1 cm2. They are both 24.6 cm long, but one is made of copper
vodka [1.7K]

Explanation:

Expression to calculate thermal resistance for iron (R_{I}) is as follows.

             R_{I} = \frac{L_{I}}{k_{I} \times A_{I}}  

where,   L_{I} = length of the iron bar

             k_{I} = thermal conductivity of iron

             A_{I} = Area of cross-section for the iron bar

Thermal resistance for copper (R_{c}) = \frac{L_{c}}{k_{c} \times A_{c}}[/tex]

where,  L_{c} = length of copper bar

             k_{c} = thermal conductivity of copper

            A_{c} = Area of cross-section for the copper bar

Now, expression for the transfer of heat per unit cell is as follows.

           Q = \frac{(100^{o} - 0^{o}}{\frac{L_{I}}{k_{I}.A_{I}} + \frac{L_{c}}{k_{c}.A_{c}}}

 Putting the given values into the above formula as follows.

       Q = \frac{(100^{o} - 0^{o})}{\frac{L_{I}}{k_{I}.A_{I}} + \frac{L_{c}}{k_{c}.A_{c}}}

  = \frac{(100^{o} - 0^{o})}{21 \times 10^{-2} m[\frac{1}{73 \times 10^{-4}m^{2}} + \frac{1}{386 \times 10^{-4}m^{2}}}

           = 2.92 Joule

It is known that heat transfer per unit time is equal to the power conducted through the rod. Hence,

                 P = \frac{Q}{T}

Here, T is 1 second so, power conducted is equal to heat transferred.

So,           P = 2.92 watt

Thus, we can conclude that 2.92 watt power will be conducted through the rod when it reaches steady state.

7 0
3 years ago
The seafloor spreading process at ridges produces what kind of faults?
irga5000 [103]
Active transform faults are between two tectonic<span> structures or faults.</span>
4 0
3 years ago
a cannonball is fired with a speed of 76 m/s from the top of a cliff. It strikes the plane below with a speed of 89 m/s. if we n
RSB [31]

Answer:

we use the formula,

v {}^{2}  = u {}^{2}  + 2gh

89 {}^{2}  = 76 {}^{2}  + 2(10)h

h = (89 {}^{2}  - 76 {}^{2} ) \div 20

h= 107 m

5 0
3 years ago
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