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liq [111]
3 years ago
11

20 Points :P

Mathematics
2 answers:
s2008m [1.1K]3 years ago
7 0

Answer:

0

Step-by-step explanation:

omeli [17]3 years ago
5 0
I believe where the graph is increasing is at 2 on the graph. it is showing it is increasing upwards.
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On a coordinate plane, 2 triangles are shown. The first triangle has points A (1, 4), B (3, 4), C (3, 2). The second triangle ha
maw [93]

Answer:

R0, 90°

Step-by-step explanation:

6 0
3 years ago
Please help me!!!!!
chubhunter [2.5K]

Answer:

y = - \frac{2}{5} (x - 5)² + 7

Step-by-step explanation:

The equation of a quadratic in vertex form is

y = a(x - h)² + k

where (h, k ) are the coordinates of the vertex and a is a multiplier

Here (h, k ) = (5, 7 ) , then

y = a(x - 5)² + 7

To find a substitute (10, - 3 ) into the equation

- 3 = a(10 - 5)² + 7 ( subtract 7 from both sides )

- 10 = 5²a = 25a ( divide both sides by 25 )

\frac{-10}{25} = a , that is

a = - \frac{2}{5}

y = - \frac{2}{5} (x - 5)² + 7 ← in vertex form

8 0
2 years ago
Find the sum of a finite geometric series. The sides of an equilateral triangle measure 16 inches. The midpoints of the sides of
olga2289 [7]
48 + 24 + 12 + 6 = 90 inches or <span>3*(16+8+4+2) = 90 will be the right answer.</span>
7 0
3 years ago
Read 2 more answers
There are 52 weeks in a year. Ben has lived in london for two fifths of year. How many weeks has ben lived in london?
masha68 [24]

Answer:

\frac{104}{5} weeks or 20\frac{4}{5} weeks

Step-by-step explanation:

To do this we can set up a proportion

\frac{52}{1} *\frac{2}{5}

This will tell us how many weeks are in 2/5 of a year

Let's evaluate this

\frac{104}{5}

We cannot simplifiy this anymore, so we will leave it as an improper fraction, or a mixed number as shown below

20\frac{4}{5} weeks

5 0
3 years ago
Read 2 more answers
if about 32,834.5 kilobytes of memory is still available how many more pictures can they take if you have only taken 43 pictures
oksano4ka [1.4K]
That will depend, you have to ask yourself first how many kilobytes one picture is. Let's just say that the size of one picture is 100 kb (which is the average size of a picture) Then first you multiply 100 kb with the number of pictures which is 43. Now you have a total used up memory of 4300 kb. After that, you minus the used up memory which is 4300 kb, to the total available space which is 32,834.5 and you will get an available space of 28534.5 kb. After that, you divide the remaining available space with the size of each picture. So this will be 28534.5 divided by 100. You will get 285. You can still take 285 pictures. 
5 0
3 years ago
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