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quester [9]
3 years ago
14

What are the bases that pair up to bake up the rugs of DNA ladder

Chemistry
2 answers:
Allushta [10]3 years ago
8 0
Nitrogeous bases. adenine, thymine, cytosine,and guanine.
Effectus [21]3 years ago
6 0
I'm not completely sure but if I did know I would definitely tell u
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Consider the reaction. 2 Al ( s ) + Fe 2 O 3 ( s ) heat −−→ Al 2 O 3 ( s ) + 2 Fe ( l ) If 17.3 kg Al reacts with an excess of F
IrinaVladis [17]

Answer:

32.7 kilograms of aluminium oxide  will be produced.

Explanation:

2 Al ( s ) + Fe_2O_3 ( s ) +heat\rightarrow Al_2O_3 ( s ) + 2 Fe ( l )

Mass of aluminum = 17.3 kg = 17300 g (1 kg = 1000 g )

Moles of aluminium = \frac{17300 g}{27 g/mol}=640.74 mol

According to reaction, 2 moles of aluminum gives 1 mole of aluminum oxide,then 640.74 moles of aluminum will give:

\frac{1}{2}\times 640.74 mol= 320.37 mol of aluminum oxide

Mass of 320.37 moles of aluminum oxides:

320.37 mol × 102 g/mol = 32,677.74 g = 32.67774 kg ≈ 32.7 kg

32.7 kilograms of aluminium oxide  will be produced.

6 0
3 years ago
How many electrons are in a s-2 ion​
Zielflug [23.3K]

Answer:

the ion will have additional 2 electrons so it will be 18

6 0
3 years ago
What is the usable form of nitrogen that is found in the ground?
laila [671]
Nitrate

Hope this helps :))
5 0
3 years ago
During the drying cycle, clothes soaked in liquid PERC at 300 K at 1 atm are tumbled in a stream of warm air at 330 K at 1 atm t
djyliett [7]
The answer is option A
6 0
3 years ago
0.500 L of a gas is collected at 2911 MM and 0°C. What will the volume be at STP?
ioda

Answer:

V₂ =  1.92 L

Explanation:

Given data:

Initial volume = 0.500 L

Initial pressure =2911 mmHg (2911/760 = 3.83 atm)

Initial temperature = 0 °C (0 +273 = 273 K)

Final temperature = 273 K

Final volume = ?

Final pressure = 1 atm

Solution:

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

by putting values,

V₂ = P₁V₁ T₂/ T₁ P₂  

V₂ = 3.83 atm × 0.500 L × 273 K / 273 K × 1 atm

V₂ = 522.795 atm .L. K / 273 K.atm

V₂ =  1.92 L

4 0
3 years ago
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