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torisob [31]
3 years ago
13

What is the net force on a truck if the force of friction is 31 N and the force of the engine is 79 N?

Physics
1 answer:
NeTakaya3 years ago
6 0

Answer:  C) 48 N forward

===================================================

Explanation:

Subtract the two forces, since they are working opposite one another.

79-31 = 48

The net force is 48 newtons forward. The truck is moving forward since the engine's force (79 N) is larger than the force of friction (31 N).

The force of friction cannot exceed the engine's force because friction only slows down an object, and does not push the object backward. In other words, if the object was stationary, then the ground isn't pushing the object backwards assuming you're on a level flat ground.

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Two falling inflated balls of different masses<br> land at the same time.
Mashcka [7]

Answer:

true two falling inflated balls of different mass lands at the smae time because gravity acts to both in a same way

8 0
3 years ago
A jet accelerates from rest down a runway at 1.75m/s² for a distance of 1500 m before takeoff.
babunello [35]
A. Using the third equation of motion:
v2 = u2 + 2as
from the question;
the jet was initially at rest
hence u = 0
a = 1.75m/s2
s = 1500m
v2 = 02 + 2(1.75)(1500)
v2 = 5250
v = √5250
v = 72.46m/s
hence it moves with a velocity of 72.46m/s.
b. s = ut + 1/2at2
1500 = 0(t) + 1/2(1.75)t2
1500 × 2 = 2× 1/2(1.75)t2
3000 = 1.75t2
1714.29 = t2
41.4 = t
hence the time taken for the plane to down the runway is 41.4s.


Read more on Brainly.com - brainly.com/question/18743384#readmore
8 0
3 years ago
A single-turn circular loop of wire of radius 45 mm lies in a plane perpendicular to a spatially uniform magnetic field. During
Lina20 [59]

Answer:

Magnitude of induced emf is 0.00635 V

Explanation:

Radius of circular loop r = 45 mm = 0.045 m

Area of circular loop A=\pi r^2

A=3.14\times 0.045^2=0.00635m^2

Magnetic field is increases from 250 mT to 350 mT

Therefore change in magnetic field dB=250-350=100mT

Emf induced is given by

e=-N\frac{d\Phi }{dt}=-NA\frac{dB}{dt}

e=-0.00635\times \frac{100\times 10^{-3}}{0.10}=-0.00635V

Magnitude of induced emf is equal to 0.00635 V

7 0
3 years ago
Fruits and vegetables should take up half you plate at a meal.<br> A. <br> True<br> B. <br> False
umka21 [38]

Answer:

A. true

Explanation:

3 0
2 years ago
Read 2 more answers
A person is attracted towards the center of the earth by an 800 N gravitational force. The force with which the earth is attract
suter [353]

Answer:

800 N

Explanation:

By Newton's third law which states that for every action, there is an equal and opposite reaction.

So, as the earth attracts the person towards its center, the person attracts the earth towards itself with the same magnitude of force but in the opposite direction.

Since the person is attracted towards the center of the earth by an 800 N gravitational force, the  the earth is attracted toward the person with an 800 N reaction force.

7 0
2 years ago
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