Answer:
Most organic compounds contain carbon and <u>hydrogen</u>.
Explanation:
Organic compounds are class of compounds which mainly constitute carbon and other elements like hydrogen, oxygen, nitrogen and sulfur etc.
In these compounds hydrogen is essentially present along with carbon as both make the basic organic class of compounds namely, Alkanes (saturated hydrocarbons), Alkenes and Alkynes (unsaturated hydrocarbons).
While remaining classes of organic compounds are derived from these three classes of hydrocarbons. Therefore, we can conclude that organic compounds are basically made up of carbon and hydrogen.
The percent error associated with Jason’s measurement is 0.596%.
HOW TO CALCULATE PERCENTAGE ERROR:
- The percentage error of a measurement can be calculated by following the following process:
- Find the difference between the true value and the measured value of a quantity.
- Then, divide by the true value and then multiplied by 100
- The true value of the density of iron is 7.874 g/mL
- Jason observed value is 7.921 g/mL
Difference = 7.921 g/mL - 7.874 g/mL
Difference = 0.047 g/mL
Percentage error = 0.047/7.874 × 100
Percentage error = 0.596%.
Therefore, the percent error associated with Jason’s measurement is 0.596%.
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12 HClO₄ + 1 P₄O₁₀ → 4 H₃PO₄ + 6 Cl₂O₇
<h3>Explanation</h3>
Balance by the conservation of atoms.
Assign coefficient <em>1 </em>to the species with the largest number of elements and atoms. H₃PO₄ contains three elements. Each of its molecule contains eight atoms, that's two more than the six atoms in a HClO₄ molecule. Start by assigning H₃PO₄ a coefficient of <em>1</em>.
? HClO₄ + ? P₄O₁₀ → <em>1</em> H₃PO₄ + ? Cl₂O₇
There are now three H atoms, one P atom on the product side. H₃PO₄ is the only product that contains H and P atoms. As a result, there should be the same number of H and P atoms on the reactant side.
- Among all reactants, only HClO₄ contains H atoms. Each HClO₄ molecule contains one H atom. Three H atoms correspond to three HClO₄ molecule.
- Among all reactants, only P₄O₁₀ contains P atoms. Each P₄O₁₀ molecule contains four P atoms. One P atom corresponds to 1/4 of a P₄O₁₀ molecule.
Thus
<em>3</em> HClO₄ + <em>1/4</em> P₄O₁₀ → <em>1</em> H₃PO₄ + ? Cl₂O₇
There are three Cl atoms in three HClO₄ molecules. HClO₄ is the only species that contains Cl among all reactants. There are three Cl atoms on the reactant side and shall be the same number of Cl atoms on the product side.
- Cl₂O₇ is the only molecule that contains Cl among the products. Each Cl₂O₇ molecule contains two Cl atoms. Three Cl atoms will correspond to 3/2 Cl₂O₇ molecules.
<em>3</em> HClO₄ + <em>1/4</em> P₄O₁₀ → <em>1</em> H₃PO₄ + <em>3/2</em> Cl₂O₇
Multiply both sides by the least common multiple of the denominators to eliminate the fraction. The least common multiple in this case is four.
12 HClO₄ + 1 P₄O₁₀ → 4 H₃PO₄ + 6 Cl₂O₇
Answer:
1. H₂SO₄ + Na₂CO₃ ⇒ Na₂SO₄ + H₂O + CO₂
sulfuric acid + sodium carbonate ⇒ sodium sulfate + water + carbon dioxide
2. 2 HCl + Mg(HCO₃)₂ ⇒ MgCl₂ + 2 H₂O + 2 CO₂
hydrochloric acid + magnesium hydrogencarbonate ⇒ magnesium chloride + water + carbon dioxide
Explanation:
1. Sulfuric acid is H₂SO₄. Sodium carbonate is Na₂CO₃.
H₂SO₄ + Na₂CO₃ ⇒ Na₂SO₄ + H₂O + CO₂
sulfuric acid + sodium carbonate ⇒ sodium sulfate + water + carbon dioxide
2. Hydrochloric acid is HCl. Magnesium hydrogencarbonate is Mg(HCO₃)₂.
2 HCl + Mg(HCO₃)₂ ⇒ MgCl₂ + 2 H₂O + 2 CO₂
hydrochloric acid + magnesium hydrogencarbonate ⇒ magnesium chloride + water + carbon dioxide
Answer :
The Nernst equation :
![E_{cell}=E^o_{cell}-\frac{2.303RT}{nF}\log \frac{[Anode]}{[Cathode]}](https://tex.z-dn.net/?f=E_%7Bcell%7D%3DE%5Eo_%7Bcell%7D-%5Cfrac%7B2.303RT%7D%7BnF%7D%5Clog%20%5Cfrac%7B%5BAnode%5D%7D%7B%5BCathode%5D%7D)
where,
= standard cell potential
n = number of electrons in oxidation-reduction reaction
F = Faraday constant = 96500 C
R= gas constant = 8.314 J/Kmol
T = temperature
[Anode] = anodic ion concentration
[Cathode] = cathodic ion concentration
