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3 years ago

What is the volume of a sample of ammonia gas (NH3) if it contains 0.23 moles?

Chemistry

1 answer:

LekaFEV [45]3 years ago

8 0

The volume of a sample of ammonia gas : 5.152 L

<h3>Further explanation</h3>

Given

0.23 moles of ammonia

Required

The volume of a sample

Solution

Assumed on STP

Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters / mol.

So for 0.23 moles :

= 0.23 x 22.4 L

= 5.152 L

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3 years ago

0.265g of an organic compound produced an evaporation 102cm³ of vapour at 373k and 775mmHg percentage composition of the constit

kumpel [21]

A. The molecular mass of the compound is 77.9 g/mol

B. The molecular formula of the compound is C₆H₆

<h3><u>Determination of the mole of the compound</u></h3>

We'll begin by calculating the number of mole of compound using the ideal gas equation as shown below:

Volume (V) = 102 cm³ = 102 / 1000 = 0.102 L

Temperature (T) = 373 K

Pressure (P) = 775 mmHg = 775 / 760 = 1.02 atm

Gas constant (R) = 0.0821 atm.L/Kmol

Number of mole (n) =?

n = PV / RT

n = (1.02 × 0.102) / (0.0821 × 373)

n = 0.0034 mole

<h3><u>A.</u><u> Determination of the </u><u>molecular mass</u><u> of the </u><u>compound</u><u>. </u></h3>

Mass = 0.265 g

Number of mole = 0.0034 mole

Molecular mass =?

Molecular mass = mass / mole

Molecular mass = 0.265 / 0.0034

Molecular mass of compound = 77.9 g/mol

<h3><u>B</u><u>. Determination of the </u><u>molecular formula</u><u> of the compound. </u></h3>

We'll begin by calculating the empirical formula of the compound.

Carbon (C) = 92.24%

Hydrogen (H) = 7.76%

Empirical formula =?

Divide by their molar mass

C = 92.24 / 12 = 7.69

H = 7.76 / 1 = 7.76

Divide by the smallest

C = 7.69 / 7.69 = 1

H = 7.76 / 7.69 = 1

Thus the empirical formula of the compound is CH

Finally, we shall determine the molecular formula.

Molecular mass = 77.9 g/mol

Empirical formula = CH

Molecular formula =?

Molecular formula = empirical × n = molecular mass

[CH]n = 77.9

[12 + 1]n = 77.9

13n = 77.9

Divide both side by 13

n = 77.9 / 13

n = 6

Molecular formula = [CH]n

Molecular formula = [CH]₆

Molecular formula = C₆H₆

Complete Question:

0.265g of an organic compound produced on evaporation 102cm cube of vapour at 373K and 775mmHg. Percentage composition of the constituent elements are 92.24% C and 7.76% H. Find the molecular mass and molecular formula of the composition.

Learn more about ideal gas equation:

brainly.com/question/14364992

Learn more about molecular formular:

brainly.com/question/512891

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2 years ago

A block of iron has a mass of 826 g. What is the volume of the block of iron whose density at 25°C is 7.9

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Answer:

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Explanation:

Density = mass/volume

therefore volume = mass/density

826/7.9=105 (To three significant figure)

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How many atoms of phosphorus are in 8.10 mol of copper(II) phosphate?

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3 years ago

What is the volume of a sample of ammonia gas (NH3) if it contains 0.23 moles?​

What is the volume of a sample of ammonia gas (NH3) if it contains 0.23 moles?