A stuntman jumps from the roof of a building to the safety net below. How far has the stuntman fallen after 2.3 seconds? A. 25.9
1 answer:
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Answer:
a)52.58 m/s
b)56.13°
Explanation:
assume the upward direction as positive
x-component of the velocity = 29.3×cos33.6°=24.40 m/s (remain constant)
y-component of the velocity which is -29.3sin33.6°= -16.21 m/s
time of flight = 68.3/24.40= 2.7991 seconds
now, we can obtain final velocity in y-direction
=43.66 m/s
=52.58 m/s
for direction
56.13° from the horizontal