Answer:
x3 – 7x2 + 3------ x3 - 7x2 + 3
3x3 + x2-----------x2 • (3x + 1)
x2 + 4x - 3------------ x2 + 4x - 3
Step-by-step explanation:
Step 1 :
Equation at the end of step 1 :
((x3) - 7x2) + 3
Step 2 :
Polynomial Roots Calculator :
2.1 Find roots (zeroes) of : F(x) = x3-7x2+3
Polynomial Roots Calculator is a set of methods aimed at finding values of x for which F(x)=0
Rational Roots Test is one of the above mentioned tools. It would only find Rational Roots that is numbers x which can be expressed as the quotient of two integers
The Rational Root Theorem states that if a polynomial zeroes for a rational number P/Q then P is a factor of the Trailing Constant and Q is a factor of the Leading Coefficient
In this case, the Leading Coefficient is 1 and the Trailing Constant is 3.
The factor(s) are:
of the Leading Coefficient : 1
of the Trailing Constant : 1 ,3
Let us test ....
P Q P/Q F(P/Q) Divisor
-1 1 -1.00 -5.00
-3 1 -3.00 -87.00
1 1 1.00 -3.00
3 1 3.00 -33.00
Hope this helps.
Answer:
$147.80
Step-by-step explanation:
140 x .0557 = 7.80 Tax
Add tax to price
140 + 7.80 = $147.80
There are 8 students in each class and there are 5 classes
: )
Answer:
12
Step-by-step explanation:
x^2 - a
If a is a perfect square we could factor
x^2 - b^2 = (x-b)(x+b)
So a cannot be 36,49,81 since they are perfect squares
a must be 12
Answer:
50 km/hr
Step-by-step explanation:
OK, this is how I solved this problem.
Let r = original rate of speed
t = time after the stop to finish the trip
Time for trip without stopping is 225/r
(1) 1.5 + .5 + t = 225/r This is a time equation
(2) 1.5r + t(r + 10) = 225 This is a distance equation
(1) 2 + t = 225/r (2) 1.5r + tr + 10t = 225
2r + tr = 225
tr = 225 - 2r 1.5r + 225 - 2r + 10(225/r - 2) = 225
t = 225/r - 2
-.5r + 225 + 2250/r - 20 = 225
-5r + 2250 + 22500/r - 200 = 2250
-5r^2 + 2250r + 22500 - 200r = 2250r
5r^2 + 200r - 22500 = 0
5(r^ + 40r - 4500) = 0
5(r - 50)(r + 90) = 0
r = 50 or r = -90
The rate cannot be negative, so the original speed 50 km/hr
This not an easy problem and I hope you were able to follow my work
