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umka21 [38]
3 years ago
12

Sort the length measurements in increasing order of magnitude from smallest to largest Drag each tile to the correct box Tiles S

equence micrometer Kilometer decimeter centimeter nanometer dekameter
Physics
1 answer:
wariber [46]3 years ago
3 0

Answer:

Nanometer, micrometer, centimeter, decimeter, dekameter, kilometer

Explanation:

Given the following length measurement :

micrometer Kilometer decimeter centimeter nanometer dekameter.

Sorting in increasing order of magnitude from Smallest to Largest.

Expressing in terms of meters :

1 meter = 0.1 decameter

1 meter = 1 × 10^9 nanometer

1 meter = 1 × 10^2 centimeter

1 meter = 1 × 10^1 decimeter

1 meter = 0.001 kilometer

1 meter = 1 × 10^6 micrometers

Hence, arranging from Smallest to Largest :

Nanometer, micrometer, centimeter, decimeter, dekameter, kilometer

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First we need to write down heat capacity for water which is constant.
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The equation for Energy that we will be calculating is:

E=cp*m*T
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E = 4186*100*333,15 = 139 456 590 J
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Explanation:

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8 0
3 years ago
A horizontal spring with spring constant 130 N/m is compressed 17 cm and used to launch a 2.8 kg box across a frictionless, hori
olasank [31]

Explanation:

The given data is as follows.

        k = 130 N/m,       \Delta x = 17 cm = 0.17 m   (as 1 m = 100 cm)

     mass (m) = 2.8 kg

When the spring is compressed then energy stored in it is as follows.

             Energy = \frac{1}{2}kx^{2}

Now, spring energy gets converted into kinetic energy when the box is launched.

So,    \frac{1}{2}kx^{2} = \frac{1}{2}mv^{2}

   \frac{1}{2} \times 130 \times (0.17)^{2} = \frac{1}{2} \times 2.8 \times v^{2}

          v^{2} = \frac{3.757}{2.8}

                     = 1.34

                v = 1.15 m/sec

Now,

           Frictional force = \mu \times mg

                                    = 0.15 \times 2.8 \times 9.8

                                    = 4.116 N

Also,  Kinetic energy = work done by friction

           \frac{1}{2}mv^{2} = F_{f} \times d

           \frac{1}{2} \times 2.8 \times (1.15)^{2} = 4.116 \times d

             1.8515 = 4.116 \times d

                 d = 0.449 m

Thus, we can conclude that the box slides 0.449 m across the rough surface before stopping.

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3 years ago
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guajiro [1.7K]
The answer is parallel

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I hope this helps! :3
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