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DerKrebs [107]
3 years ago
5

You walk 200m south, then 50m east. What is your displacement?

Physics
1 answer:
vredina [299]3 years ago
5 0
250m good luck onnur test
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PLS HELP ME
NeTakaya
The answer is true...
4 0
3 years ago
What principle is responsible for alternating light and dark bands when light passes through two or more narrow slits? What prin
kipiarov [429]

Answer:

Interference

Explanation:

When two waves of same frequency and constant phase difference super impose at a point on the screen then due to their superposition we will get different intensity of light at different positions of the screen

This phenomenon of redistribution of energy is known as interference of light.

So at the position of screen where the light intensity is maximum on the screen is known as constructive interference while the positions on the screen where it will get minimum intensity on the screen is known as destructive interference of the light

So correct answer would be

Interference

4 0
3 years ago
Andy and Charlie are riding on a merry-go-round. Andy rides on a horse at the outer rim of the circular platform, twice as far f
Volgvan

Complete Question:

Andy and Charlie are riding on a merry-go-round. Andy rides on a horse at the outer rim of the circular platform, twice as far from the center of the circular platform as Charlie, who rides on an inner horse. When the merry-go-round is rotating at a constant angular speed, which of the following best describes Andy's angular speed?'

( ) twice Charlie’s

( ) impossible to determine.

( ) the same as Charlie’s

( ) half of Charlie’s

Answer:

The same as Charlie's

Explanation:

As a merry-go-round is a rigid body, all points in the rotating body must have the same angular velocity, i.e., thet must rotate the same angle in the same time.

Otherwise, the distance between any pair of points on a given radius could be different in different times, which is not possible in a rigid body,

3 0
3 years ago
Salmon often jump waterfalls to reach their
Y_Kistochka [10]

Answer:

5.38 m/s

Explanation:

Given (in the x direction):

Δx = 2.45 m

v₀ = v cos 42.5°

a = 0 m/s²

Δx = v₀ t + ½ at²

(2.45 m) = (v cos 42.5°) t + ½ (0 m/s²) t²

2.45 = (v cos 42.5°) t

t = 3.32 / v

Given (in the y direction):

Δy = 0.373 m

v₀ = v sin 42.5°

a = -9.8 m/s²

Δx = v₀ t + ½ at²

(0.373 m) = (v sin 42.5°) t + ½ (-9.81 m/s²) t²

0.373 = (v sin 42.5°) t − 4.905 t²

0.373 = (v sin 42.5°) (3.32 / v) − 4.905 (3.32 / v)²

0.373 = 2.25 − 54.2 / v²

v = 5.38

Graph:

desmos.com/calculator/5n30oxqmuu

4 0
3 years ago
.prove : s=ut +½ at²​
o-na [289]

Explanation:

Let the distance covered by the body be s, initial and final velocities be u and v respectively and time taken be t.

\therefore Average\: velocity = \frac{u+v}{2} \\\\Now, \:we \:know\: that\\\\Distance \:covered\\ = Average\: velocity \times time\\\\\therefore s= \frac{(u+v) }{2} \times t..... (1)\\\\

By first equation of motion:

v = u + at

Substituting the value of v in equation (1), we find:

s= \frac{(u+u + at)}{2} \times t\\\\\therefore s= \frac{(2u + at)}{2} \times t\\\\\therefore s= \frac{(2ut + at^2)}{2}\\\\\therefore s=  \frac{2ut} {2}+ \frac{at^2}{2}\\\\   \huge \orange {\boxed {\therefore s= ut+ \frac{1}{2}at^2}} \\\\

Hence proved.

6 0
3 years ago
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