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iren2701 [21]
3 years ago
7

Earth is subject not only to the gravitational force of the Moon but also to the gravitational pull of the Sun. However, Earth i

s much farther away from the Sun than it is from the Moon. In fact, the center of Earth is at an average distance of 1.5×1011m from the center of the Sun. Given that the mass of the Sun is 1.99×1030kg, which of the following statements is correct?
A. The force exerted on Earth by the Sun is weaker than the corresponding force exerted by the Moon.
B. The force exerted on Earth by the Sun is stronger than the corresponding force exerted by the Moon.
C. The force exerted on Earth by the Sun is of the same order of magnitude of the corresponding force exerted by the Moon.
Physics
1 answer:
Margaret [11]3 years ago
4 0

Answer:

option (B)

Explanation:

The gravitational force on earth depends on the mass of sun and the distance of sun from earth.

As the mass of sun is much more than the mass of moon, so the gravitational force of sun on earth is much more than the force on earth due to the moon.

The distance does not matter because the mass of sun is much more.

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IceJOKER [234]
The average speed of the football is 15 meters per second. Just divide both of the numbers by 4 :)
6 0
4 years ago
These questions !plz !! i need help!!!
Nataly_w [17]

(6) Wagon B is at rest so it has no momentum at the start. If <em>v</em> is the velocity of the wagons locked together, then

(140 kg) (15 m/s) = (140 kg + 200 kg) <em>v</em>

==>   <em>v</em> ≈ 6.2 m/s

(7) False. If you double the time it takes to perform the same amount of work, then you <u>halve</u> the power output:

<em>E</em> <em>/</em> (2<em>t </em>) = 1/2 × <em>E/t</em> = 1/2 <em>P</em>

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3 0
3 years ago
An airplane starts from A and flies to B at a constant speed. After reaching B it returns to A at the same speed. There was no w
Dafna1 [17]

Answer:

When there is wind it takes longer

Explanation:

With no wind, the round trip time is

t_1=\frac{d}{v}+\frac{d}{v}=\frac{2d}{v}

When we have a constant wind speed w

t_2=\frac{d}{v-w} +\frac{d}{v+w} =\frac{2vd}{v^{2} -w^{2}}

comparing the reciprocal times;

\frac{1}{t_2}=\frac{v^{2}-w^{2} }{2vd}=\frac{v}{2d}-\frac{w^{2}}{2vd}   \leq \frac{v}{2d}=\frac{1}{t_1}

This means that t1 is smaller than t2, ergo, it takes longer with wind

4 0
3 years ago
The average specific heat of the human body is 3.6 kJ/kg·°C. If the body temperature of a(n) 96-kg man rises from 37°C to 39°C d
d1i1m1o1n [39]

Answer:

691200 J

Explanation:

From specific heat capacity,

ΔQ = cmΔt.................. Equation 1

Where ΔQ = increase in thermal energy, c = specific heat capacity of the body, m = mass of the man, Δt = rise in temperature.

Given: c = 3.6 kJ/kg.°C = 3600 J/kg.°C, m = 96 kg, Δt = 39-37 = 2 °C.

Substitute into equation 1

ΔQ = 3600×96×2

ΔQ = 691200 J.

Hence the change in the thermal energy of the body = 691200 J

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3 years ago
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Andreas93 [3]

Answer:2

Explanation:

6 0
3 years ago
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