Explain what happens during stages A and B.

The area vector of a square loop of 5 turns of a conductor each with side length of 0.2 m carrying a current of 2 A is antiparal

Anon25 [30]

Answer:

$M= 0.4 Am^2$

Explanation:

From the question we are told that:

Number of turns $N=5$ $N=5$

Conductor each with side length $L=0.2m$

Current $I=2A$

Magnetic field $B=50.0T$

Generally the equation for the total magnetic moment M is mathematically given by

$M = current * area$

$M= I * A$

$M = 2 * (5* 0.2*0.2)$

$M = 2 * 0.2$

$M= 0.4 Am^2$

3 0

3 years ago

A dolphin can swim at a constant speed of 12.5 m/s. How

myrzilka [38]

Answer:

$\boxed {\tt 3.6 \ seconds}$

Explanation:

Time can be found by dividing the distance by the speed.

$t=\frac{d}{s}$

The distance is 45 meters and the speed is 12.5 meters per second.

$d= 45 \ m \\s= 12.5 \ m/s$

$t=\frac{45 \ m}{12.5 \ m/s}$

Divide. Note that the meters, or "m" will cancel each other out.

$t=\frac{45 }{12.5 \ s}$

$t=3.6 \ s$

It will take the dolphin 3.6 seconds to swim a distance of 45 meters are 12.5 meters per second.

6 0

3 years ago

Read 2 more answers

In an inelastic collision a 2.5 kg ball moving at 7.5 m/s is caught by a 70kg man while the man is standing on ice. What is the

MrRa [10]

The velocity of the ball and the man is 0.259 m/s

Explanation:

We can solve this problem by using the law of conservation of momentum. In fact, in an isolated system, the total momentum before and after the collision must be conserved. Therefore, for the ball-man system, we can write:

$p_i = p_f\\m_1 u_1 + m_2 u_2 = (m_1+m_2)v$

where:

$m_1 = 2.5 kg$ is the mass of the ball

$u_1 = 7.5 m/s$ is the initial velocity of the ball

$m_2 = 70 kg$ is the mass of the man

$u_2 = 0$ is the initial velocity of the man

$v$ is the final velocity of the man and the ball after the collision

Re-arranging the equation and substituting the values, we find the final velocity:

$v=\frac{m_1 u_1}{m_1+m_2}=\frac{(2.5)(7.5)}{2.5+70}=0.259 m/s$

So, the man and the ball slides on the ice at 0.259 m/s.

Learn more about momentum:

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#LearnwithBrainly

3 0

3 years ago

If the emf produced in a wire is 0.88 volts and the wire moves perpendicular to a magnetic field of strength 0.075 newtons/amper

Elza [17]

Emf = d (phi-B) / dt
B dA/dt, where dA/dt is the area swept out by the wire per unit time. 
0.88 V = (0.075 N/(A m)) (L)(4.20 m/s), so 
L = (0.88 J/C) / [ (0.075 N s/C m)(4.2 m/s) ] = about 3 meters

6 0

3 years ago

Read 2 more answers

What is the separation distance, in meters, between masses m1 = 15 x 107 kg and m2 = 62 x 107 kg when the gravitational force be

nalin [4]

Answer:

94.1 m

Explanation:

From Coulombs law,

F = Gm1m2/r²................... Equation 1

where F = force, m1 = first mass, m2 = second mass, G = universal constant, r = distance of separation.

Make r the subject of the equation,

r = √(Gm1m2/F)................. Equation 2

Given: F = 7×10² N, m1 = 15×10⁷ kg, m2 = 62×10⁷ kg,

Constant: G = 6.67×10⁻¹¹ Nm²/kg²

Substitute into equation 2

r = √( 6.67×10⁻¹¹×15×10⁷×62×10⁷/7×10²)

r √(886.16×10)

r √(88.616×10²)

r = 9.41×10

r = 94.1 m.

Hence the distance of separation = 94.1 m

3 0

3 years ago