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monitta
3 years ago
7

Explain what happens during stages A and B.

Physics
1 answer:
fgiga [73]3 years ago
3 0
Is there a picture?
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0.054x2.33x90............
guapka [62]
<h2>0.054×2.33×90</h2><h3>=0.11582×90</h3><h3>=11.3238</h3>

please mark this answer as brainlist

5 0
3 years ago
calculate the percentage contraction of a rod moving with a velocity of 0.8c in a direction inclined at 60° to its own length​
hram777 [196]

Answer:

Let lo be the length of the rod in the frame in which it is at rest and s' is the frame which is moving with a speed 0.8c in a direction making an angle 60° with x-axis. The components of lo along and perpendicular to the direction of motion are lo cos 60° and lo sin 60° respectively.

Now length of the rod along the direction of motion

= lo cos 60°_/1-(0.8) 2/c2

= lo/2×0.6

= 0.3 lo.

Length of the rod perpendicular to the direction of motion.

= lo sin 60°

=_/3/2 lo

Length of moving rod

l = [(0.3lo)2+{lo_/3/2} 2] 1/2

= 0.916 lo.

Percentage contraction

= lo-0.916lo/lo×100

= 8.4%.

Explanation:

<h2><u><em>Brainliest?</em></u></h2>
4 0
3 years ago
Help me with this please
Jobisdone [24]

Answer:

Option D- 1,2 and 3

Explanation:

Gravity always acts on an object irrespective of height

4 0
3 years ago
Read 2 more answers
A. while<br>to rest<br>coming<br>down from a slide<br>you stop and come​
Pani-rosa [81]
Ok ok ok ok ok ok I ok ok I I’m only on kn knkkkm I’m on
3 0
3 years ago
What is a centripetal acceleration of a point on a bicycle wheel of a radius of 0.70 m when a bike is moving 8.0 m/s
Furkat [3]

Answer:

The acceleration of a point on the wheel is 11.43 m/s² acting radially inward.

Explanation:

The centripetal acceleration acts on a body when it is performing a circular motion.

Here, a point on the bicycle is performing circular motion as the rotation of the wheel produces a circular motion.

The centripetal acceleration of a point moving with a velocity v and at a distance of r from the axis of rotation is given as:

a=\frac{v^2}{r}

Here, v=8\ m/s,r=0.70\ m

∴ a=\frac{8}{0.70}=11.43\ m/s^2

Therefore, the acceleration of a point on the wheel is 11.43 m/s² acting radially inward.

3 0
4 years ago
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