Answer:
(a) Electrostatic force F=4.51×10⁻¹⁷N
(b) Number of electron n=4425 electrons
Explanation:
Given data
Charges q₁=q₂= -7.08×10⁻¹⁶C
Distance r=1.00cm =0.01 m
To find
(a) Electrostatic force F
(b) Number of electron n
Solution
For (a) Electrostatic force
From Coulombs law we know that
For (b) number of electron n
The number of electron on the drop that giving it its imbalance is the total charge divided by charge of electron
As we now that charge of electron e= -1.6×10⁻¹⁹C
I'm pretty sure the study is known as paleomagnetism
S = d/t
s = 1396/4 = 349m/s
Answer:
Explanation:
for the calculation of the electric potential inside a parallel plate capacitor you can use the formula for the electric field inside the capacitor.
where d is the distance between plates and E is the electric field, which is given by:
By replacing you obtain:
where Q is the charge stored by the capacitor and A is the area of the plates.
hence, the answer is Qd/Ae0