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jarptica [38.1K]
4 years ago
11

PLEASE ANSWER ALL! CORRECT ANSWERS ONLY!!!!

Physics
1 answer:
Alex777 [14]4 years ago
3 0

Distance is a scalar quantity. It refers only to how far an object has traveled. For example, 4 feet is a distance; it gives no information about direction. To say an object traveled 4 feet is somewhat ambiguous. To say the object traveled 4 feet west, for example, would be a displacement, and would then be a vector quantity. It gives a more complete picture of what happened.

Mass is a scalar quantity. Simply put, it refers to how much matter an object is made up of. It has magnitude but gives no indication of direction in any sense. The vector counterpart to mass is weight.

Weight is a vector quantity. Weight is a force, and forces are vectors, i.e. having both magnitude and direction. Perceived weight of an object at rest on earth is given by

W

=

→

F

g

=

m

g

, the product of the mass of the object and the free-fall Time is a scalar quantity (as far as we are concerned at this level). It gives information about magnitude, i.e. how much time, but no information about direction.

Volume is a scalar quantity. It refers to the amount of space that an object occupies and therefore has magnitude, but gives no information about direction.

Density is a scalar quantity, having only magnitude and giving no information about direction. We can also reason that, because density is equal to mass divided by volume and both mass and volume are scalar quantities, density must also be a scalar quantity.

Speed is a scalar quantity, having only magnitude and giving no information about direction. For example,

40

m

s

is a speed, it tells us how fast an object is traveling, but nothing abut which direction the object is traveling in. The vector counterpart to speed is velocity.

Velocity is a vector quantity. Velocities have both magnitude and direction. For example,

40

m

s

NE is a velocity.

Acceleration is a vector quantity. Acceleration has both magnitude and direction. For example,

9.8

m

s

2

downward or

−

9.8

m

s

2

vertically is an acceleration.

Force is a vector quantity. Force has both magnitude and direction. Weight is an example of force given above. Another is the force of friction, which has some magnitude and acts in the direction opposite that of motion.

Temperature is a scalar quantity. A measurement of temperature has magnitude, but gives no information about direction.Note that certain quantities which are alone scalars can be represented as vectors when we discuss intervals or how the quantities change (e.g. measure of increase or decrease). this is all you need to know my friend

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The magnitude of the electric force between two protons is 2.30 10-26 n. how far apart are they?
SCORPION-xisa [38]
The electric force between two charge objects is calculated through the Coulomb's law.
                               F = kq₁q₂/d²
The value of k is 9.0 x 10^9 Nm²/C² and the charge of proton is 1.602 x10^-19 C. Substituting the known values from the given,
                           2.30x10^-26 = (9.0 x 10^9 Nm²/C²)(1.602 x10^-19C)²/d²
The value of d is equal to 0.10 m. 
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Explanation:

The correct answer is option D i.e. A and C

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A rocket sled with an initial mass of 3 metric tons, invluding 1 ton of fuel, rests on a level section of track. At t=0, the sol
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Answer:

v = 719.2 m / s and     a = 83.33 m / s²

Explanation:

This is a rocket propulsion system where the system is made up of the rocket plus the ejected mass, where the final velocity is

           v - v₀ = v_{e} ln (M₀ / M)

where v₀ is the initial velocity, v_{e} the velocity of the gases with respect to the rocket and M₀ and M the initial and final masses of the rocket

In this case, if fuel burns at 75 kg / s, we can calculate the fuel burned for the 10 s

            m_fuel = 75 10

            m_fuel = 750 kg

As the rocket initially had a mass of 3000 kg including 1000 kg of fuel, there are still 250 kg, so the mass of the rocket minus the fuel burned is

              M = 3000 -750 = 2250 kg

let's calculate

            v - 0 = 2500 ln (3000/2250)

            v = 719.2 m / s

To calculate the acceleration, let's use the concept of the rocket thrust, which is the force of the gases on it. In the case of the rocket, it is

             Push = v_{e} dM / dt

let's calculate

             Push = 2500  75

             Push = 187500 N

            If we use Newton's second law

             F = m a

             a = F / m

let's calculate

              a = 187500/2250

              a = 83.33 m / s²

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