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ASHA 777 [7]
3 years ago
11

The ___ model of the atom states that an electron's exact location within an atom can not be determined, but its probable locati

on can be estimated within a three-dimensional region called an atomic orbital and that an electron's properties within an orbital can only be described by a set of mathematical values called a quantum number.
Physics
1 answer:
Dima020 [189]3 years ago
5 0
The _quamtum mechanical_ model of the atom states that an electron's exact location within an atom can not be determined, but its probable location can be estimated within a three-dimensional region called an atomic orbital and that an electron's properties within an orbital can only be described by a set of mathematical values called a quantum number.
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______ are used when drawing circuit diagrams
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Light year is a unit of?
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Light year is the unit of distance. It is the distance that an object travels in one year with the speed of light.

In short, Your Answer would be "Distance"

Hope this helps!
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3 years ago
Fill in the blanks about Newton’s First Law of Motion:
Afina-wow [57]

Objects want to continue doing what they’re doing because they are “lazy.” This is called law of inertia.

Newton's first law of motion states that an object at rest or uniform motion in a straight line will continue in that state unless it is being acted upon by an external force. This law is also called the law of inertia because it depends on mass.

<em>From the given question, we can </em><em>fill gaps </em><em>as follows;</em>

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3 years ago
What is massand its si unit​
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6 0
3 years ago
a particle of mass m sits at rest at x = 0. At time t = 0 a force given by F = Fe^(-t/T) is applied in the +x direction; F and T
wlad13 [49]

Explanation:

Given:F=m\ddot{x}=Fe^{-\frac{t}{T}}

Solving for \ddot{x}:

\ddot{x}=\frac{F}{m}e^{-\sqrt{\frac{F}{m} } t}

where:

T=\sqrt{\frac{m}{F}}

Integrating to get \dot{x} with initial conditions \dot{x}(0)=0:

\dot{x}=\sqrt{\frac{F}{m}}-\sqrt{\frac{F}{m}} e^{-\sqrt{\frac{F}{m}} t}

Integrating to get x with initial conditions x(0) = 0:

x=-1+\sqrt{\frac{F}{m}} t+e^{-\sqrt{\frac{F}{m}}t}

When t=T:

x=-1+\sqrt{\frac{F}{m}}\sqrt{\frac{m}{F}}+e^{-\sqrt{\frac{F}{m}}\sqrt{\frac{m}{F}}}=\frac{1}{e}

\dot{x}=\sqrt{\frac{F}{m}}-\sqrt{\frac{F}{m}} e^{-\sqrt{\frac{F}{m}}\sqrt{\frac{m}{F}}}=\sqrt{\frac{F}{m}}(1-\frac{1}{e})

4 0
3 years ago
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