Answer:
The note in this question is not an instrument that is negotiable under Article 3 of the U.C.C. Furthermore, it is not payable at any given time on demand due to the fact that principal repayment is not covered at a specified period of time. It shows that the acceleration clause is viable for the payment of the amount upon the default of the maker. This is also for an indefinite period of time.
Explanation:
The note in this question is not an instrument that is negotiable under Article 3 of the U.C.C. Furthermore, it is not payable at any given time on demand due to the fact that principal repayment is not covered at a specified period of time. It shows that the acceleration clause is viable for the payment of the amount upon the default of the maker. This is also for an indefinite period of time.
Answer:
According to the standard Safe Practices for Motor Vehicle Operations, ANSI/ASSE Z15.1, defensive driving skills involves "driving to save lives, time, and money, in spite of the conditions around you and the actions of others."
Explanation:
Defensive driving is a type of training provided to the learners eligible to drive motor vehicles. It involves the basics of driving and rules involved in driving. The learners learn about the methods of driving safely with the minimum expense of time and money. It also helps in reducing the risks of collision in adverse situations. The methods to rescue oneself from dangerous situations are also trained. Preventing oneself from the mistakes of others is also termed under defensive driving.
Answer:
d) Is the thermal conductivity of the medium constant or variable.
Explanation:
As we know that
Heat equation with heat generation at unsteady state and with constant thermal conductivity given as
![\dfrac{d^2T}{dx^2}+\dfrac{d^2T}{dy^2}+\dfrac{d^2T}{dz^2}+\dfrac{\dot{q}_g}{K}=\dfrac{1}{\alpha }\dfrac{dT}{dt}](https://tex.z-dn.net/?f=%5Cdfrac%7Bd%5E2T%7D%7Bdx%5E2%7D%2B%5Cdfrac%7Bd%5E2T%7D%7Bdy%5E2%7D%2B%5Cdfrac%7Bd%5E2T%7D%7Bdz%5E2%7D%2B%5Cdfrac%7B%5Cdot%7Bq%7D_g%7D%7BK%7D%3D%5Cdfrac%7B1%7D%7B%5Calpha%20%7D%5Cdfrac%7BdT%7D%7Bdt%7D)
With out heat generation
![\dfrac{d^2T}{dx^2}+\dfrac{d^2T}{dy^2}+\dfrac{d^2T}{dz^2}=\dfrac{1}{\alpha }\dfrac{dT}{dt}](https://tex.z-dn.net/?f=%5Cdfrac%7Bd%5E2T%7D%7Bdx%5E2%7D%2B%5Cdfrac%7Bd%5E2T%7D%7Bdy%5E2%7D%2B%5Cdfrac%7Bd%5E2T%7D%7Bdz%5E2%7D%3D%5Cdfrac%7B1%7D%7B%5Calpha%20%7D%5Cdfrac%7BdT%7D%7Bdt%7D)
In 2 -D with out heat generation with constant thermal conductivity
![\dfrac{d^2T}{dx^2}+\dfrac{d^2T}{dy^2}=\dfrac{1}{\alpha }\dfrac{dT}{dt}](https://tex.z-dn.net/?f=%5Cdfrac%7Bd%5E2T%7D%7Bdx%5E2%7D%2B%5Cdfrac%7Bd%5E2T%7D%7Bdy%5E2%7D%3D%5Cdfrac%7B1%7D%7B%5Calpha%20%7D%5Cdfrac%7BdT%7D%7Bdt%7D)
Given equation
![\dfrac{d^2T}{dx^2}+\dfrac{d^2T}{dy^2}=\dfrac{1}{a }\dfrac{dT}{dt}](https://tex.z-dn.net/?f=%5Cdfrac%7Bd%5E2T%7D%7Bdx%5E2%7D%2B%5Cdfrac%7Bd%5E2T%7D%7Bdy%5E2%7D%3D%5Cdfrac%7B1%7D%7Ba%20%7D%5Cdfrac%7BdT%7D%7Bdt%7D)
So we can say that this is the case of with out heat generation ,unsteady state and with constant thermal conductivity.
So the option d is correct.
d) Is the thermal conductivity of the medium constant or variable.