Answer:
C. Exist
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The pressure drop of air in the bed is 14.5 kPa.
<u>Explanation:</u>
To calculate Re:

From the tables air property

Ideal gas law is used to calculate the density:
ρ = 
ρ = 1.97 Kg / 
ρ = 
R =
= 8.2 ×
/ 28.97×
R = 2.83 ×
atm / K Kg
q is expressed in the unit m/s
q = 1.24 m/s
Re =
Re = 2278
The Ergun equation is used when Re > 10,


= 4089.748 Pa/m
ΔP = 4089.748 × 3.66
ΔP = 14.5 kPa
True strain and engineering strain? True stress is defined as the load divided by the cross-sectional area of the specimen at that instant and is a true indication of the internal pressures. ... Engineering stress is defined as the load divided by the initial cross-sectional area of the specimenAnswer:
Explanation:
Answer:
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Explanation:
Answer:
The shear strain is 0.05797 rad.
Explanation:
Shear strain is the ratio of change in dimension along the shearing load direction to the height of the plate under application of shear load. Width of the plate remains same. Length of the plate slides under shear load.
Step1
Given:
Height of the pad is 1.38 in.
Deformation at the top of the pad is 0.08 in.
Calculation:
Step2
Shear strain is calculated as follows:



For small angle of
,
can take as
.

Thus, the shear strain is 0.05797 rad.