All categories

2 years ago

Help please I’ve been looking online for help but couldn’t find any.

Mathematics

1 answer:

alexandr1967 [171]2 years ago

4 0

5 is 33 because the question ends up being 14+3+16

You might be interested in

Factor completely<br> -2x^4+6x^3+8x^2

vlada-n [284]

Answer:

-2x²(x + 1)(x - 4)

Step-by-step explanation:

Hello!

Factor:

$-2x^4 + 6x^3 + 8x^2$
$-2x^2(x^2 - 3x - 4)$ Take out GCF

Think: What numbers add up to -3 and multiply to -4?

Answer: -4 and 1

Continue:

$-2x^2(x^2 - 3x - 4)$
$-2x^2(x^2 - 4x + x - 4)$
$-2x^2(x(x - 4) + 1(x - 4))$ Factor by Grouping
$-2x^2(x + 1)(x - 4)$

The complete factored form is -2x²(x + 1)(x - 4)

5 0

1 year ago

A lemonade mix calls for 2 tablespoons of mix for every 3 cups of water. If the container

nikklg [1K]

Answer:

36 cups of water

Step-by-step explanation:

Make a proportion, where x is the number of cups of water needed:

$\frac{2}{3}$ = $\frac{24}{x}$

Cross multiply and solve for x:

2x = 72

x = 36

So, 36 cups of water will be needed

4 0

3 years ago

Read 2 more answers

If thewronskian w of f and g is 3e4t,and if f(t) = e2t,find g(t).

ehidna [41]

$W(f(x),g(x))=\begin{vmatrix}f(x)&g(x)\\f'(x)&g'(x)\end{vmatrix}=f(x)g'(x)-g(x)f'(x)$

We have $f(t)=e^{2t}\implies f'(t)=2e^{2t}$ , so

$W(f(t),g(t))=e^{2t}g'(t)-2e^{2t}g(t)=3e^{4t}$
$\implies e^{-2t}g'(t)-2e^{-2t}g(t)=3$
$\implies\dfrac{\mathrm d}{\mathrm dt}[e^{-2t}g(t)]=3$
$\implies e^{-2t}g(t)=\displaystyle\int3\,\mathrm dt$
$\implies e^{-2t}g(t)=3t+C$
$\implies g(t)=3te^{2t}+Ce^{2t}$

where $C$ is any arbitrary constant.

8 0

3 years ago

A bag contains 3 red marbles, 5 yellow marbles, and 4 blue marbles. One marble is chosen at random. What is the probability that

algol13

1/3 because there's 4 blue marbles in a bag of 12 marbles so as a fraction that would be 4/12 cancelled down = 1/3

3 0

3 years ago

Fill in the blank with the correct answer choice.<br><br> 1 km = ___ m

Travka [436]

1 kilometer is 0.62 miles

1 kilometer is 1000 meters

4 0

2 years ago