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Natasha_Volkova [10]
3 years ago
14

What is accommodation in the eye? how are the muscles involved in this process?

Physics
1 answer:
ziro4ka [17]3 years ago
3 0
"Accomodation" is the name we give to our eyes' ability to change their
focus for different distances. 

Our eye does this by changing the thickness of its lens, making the lens
thicker to see nearer things, and thinner to see distant things.

The lens in the eye is suspended by a circular muscle all around it.
The muscle can pull on the circumference of the lens to make it wider
and thinner, or relax to make it narrower and thicker.

In the modern age of medical miracles that we live in, if the lens of
a person's eye is injured or becomes cloudy, an ophthalmologist can
replace it with an artificial one, and the person can see again !  But then,
the process of accommodation doesn't work any more.  That artificial lens
stays focused at the same distance all the time, and the person needs
glasses for other distances.

I can tell you that it's not really a big deal.  The lenses in BOTH of my eyes
developed "cataracts", and were replaced with artificial lenses. 
I had a choice !  I could have lenses that are good for distance, and wear
glasses for reading.  OR I could choose lenses that are good for reading
and put on glasses to see things in the distance.  I chose lenses for distance. 
I can SEE again, and I put on reading glasses when I'm reading.  

It's really a miracle when you think about it.
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An electric field of magnitude 2.35 V/m is oriented at an angle of 25.0° with respect to the positive z-direction. Determine the
zzz [600]

Answer:

The magnitude of the electric flux is 3.53\ N-m^2/C

Explanation:

Given that,

Electric field = 2.35 V/m

Angle = 25.0°

Area A= 1.65 m^2

We need to calculate the flux

Using formula of the magnetic flux

\phi=E\cdot A

\phi = EA\cos\theta

Where,

A = area

E = electric field

Put the value into the formula

\phi=2.35\times1.65\times\cos 25^{\circ}

\phi=2.35\times1.65\times0.91

\phi=3.53\ N-m^2/C

Hence, The magnitude of the electric flux is 3.53\ N-m^2/C

8 0
2 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!<br><br> Which number marks a crest?
lyudmila [28]

number 2 because the curve demstrates the crest GOOD LUCK i hope i got you the correct answer if not sorry

5 0
2 years ago
To push a 26.0 kg crate up a frictionless incline, angled at 25.0° to the horizontal, a worker exerts a force of 209 N parallel
alukav5142 [94]

Answer:

(a) W = +397.1 J

(b) W = -204.6 J

(c) W = 0

(d) W= + 192.5 J

Explanation:

Work (W) is defined as the product of force (F) by the distance (d)the body travels due to this force. :

W= F*d Formula ( 1)

The forces that perform work on an object must be parallel to its displacement.

The forces perpendicular to the displacement of an object do not perform work on it.

The work is positive (W+) if the force has the same direction of movement of the object.  

The work is negative (W-) if the force has the opposite direction of the movement of the object.

Problem development

(a) Work performed by the worker's applied force on the box .

W= 209 N * 1.9 m = +397.1 J

(b) Work performed by the gravitational force on the crate

We calculate the weight component parallel to the displacement of the box:

We define the x-axis in the direction of the inclined plane ,25.0° to the horizontal.

We define the y-axis and in the direction of the plane perpendicular to the inclined plane.

W= m*g=26*9.8= 254.8N : total box weight

Wx= W*sen25.0°= 254.8*sen25.0°= 107.68 N

W = -Wx *d =107.68 N *1.9 m= -204.6 J

(c) Work performed by normal force (N) exerted by the incline on the crate

The force N is perpendicular to the displacement, then:

W=0

(d) Total work done on the crate

W = 397.1 J -204.6 J

W = 192.5 J

4 0
2 years ago
Define speed and what is it’s SI unit.
Nadusha1986 [10]
Speed can be thought of as the rate at which an object covers distance. ... Speed has the dimensions of distance divided by time. The SI unit of speed is the metre per second, but the most common unit of speed in everyday usage is the kilometre per hour or, in the US and the UK, miles per hour........?
7 0
2 years ago
Read 2 more answers
An object is 1.0 cm tall and its erect image is 5.0 cm tall. what is the exact magnification?
ikadub [295]
The exact magnification of the objects is calculated by dividing the cinema. We calculate it by diving the erect image size by the object size. From the given above, we find the exact magnification by dividing 5.0 cm by 1.0 cm. Thus, the answer would be 5. 
7 0
2 years ago
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