What is accommodation in the eye? how are the muscles involved in this process?

1 answer:

3 0

"Accomodation" is the name we give to our eyes' ability to change their
focus for different distances.

Our eye does this by changing the thickness of its lens, making the lens
thicker to see nearer things, and thinner to see distant things.

The lens in the eye is suspended by a circular muscle all around it.
The muscle can pull on the circumference of the lens to make it wider
and thinner, or relax to make it narrower and thicker.

In the modern age of medical miracles that we live in, if the lens of
a person's eye is injured or becomes cloudy, an ophthalmologist can
replace it with an artificial one, and the person can see again ! But then,
the process of accommodation doesn't work any more. That artificial lens
stays focused at the same distance all the time, and the person needs
glasses for other distances.

I can tell you that it's not really a big deal. The lenses in BOTH of my eyes
developed "cataracts", and were replaced with artificial lenses.
I had a choice ! I could have lenses that are good for distance, and wear
glasses for reading. OR I could choose lenses that are good for reading
and put on glasses to see things in the distance. I chose lenses for distance.
I can SEE again, and I put on reading glasses when I'm reading.

It's really a miracle when you think about it.

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As you take your leisurely tour through the solar system, you come across a 1.45 kg rock that was ejected from a collision of as

nikklg [1K]

Answer:

$1.3310\times 10^8 m/s$ is the rock's speed.

Explanation:

Momentum is defined as motion possessed by the moving body's mass. Mathematically it a product of mas and velocity of the body.

$Momentum(P)=Mass(m)\times velocity(v)$

Given : Mass of rock = m = 1.45 kg

Velocity of the rock = v

Momentum of the rock = P = $1.93\times 10^8 kg m/s$

$1.93\times 10^8 kg m/s=1.45 kg\times v$

$v=\frac{1.93\times 10^8 kg m/s}{1.45 kg}=1.33\times 10^8 m/s$

$1.3310\times 10^8 m/s$ is the rock's speed.

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Which are examples of transverse waves? Check all that apply. earthquake P-waves earthquake S-waves radio waves sound visible li

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Earthquake S - Waves are examples of transverse waves. The correct option among all the options that are given in the question is the second option. Other good examples of transverse waves are an oscillating string and light waves. A wave is a kind of disturbance that or an oscillation that travels through space.

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Which statement best explains the relationship between the electric force between two charged objects and the distance between t

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Unfortunately, the given statements are missing from the problem. However, we can still determine the relationship between the electric force between two objects and the distance between them. The formula for the electric force is given below:

F = (k*Q1*Q2)/d^2

k is a constant, while Q1 and Q2 are the respective charges of the objects. F is force, while d is distance.

As seen in the formula, we can see that the electric force F is inversely proportional to the square of the distance between the two objects.

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4 years ago

A 4-kg object falls vertically a distance of 5 m. its potential energy has changed by approximately how much?

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Given:
m = 4 kg, the mass of the object
h = 5 m, distance fallen

Neglect air resistance.

The PE (potential energy) is
PE = mgh = (4 kg)*(9.8 m/s²)*(5 m) = 196 J

The PE is converted into KE (kinetic energy) after the fall.
Therefore the PE decreased by 196 J ≈ 200 J

Answer: d. It has decreased by 200 J

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4 years ago

1.2miles=__________km

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Answer:

1.931 kilometres is the answer of 1.2 miles

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3 years ago

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