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tamaranim1 [39]
3 years ago
7

An object, initially at rest, is subject to an acceleration of 34 m/s^2. How long will it take for that object to reach 3400m ?

Physics
1 answer:
Norma-Jean [14]3 years ago
6 0
Vf^2 = Vi^2 + 2ad
a= 34 m/s^2
Vi = 0 m/s
d = 3400m

Vf = 480.83 m/s

a=v/t
t=v/a
t=480.83/34
t=14.142 s
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6 0
3 years ago
Two children, Ahmed and Jacques, ride on a merry-go-round. Ahmed is at a greater distance from the axis of rotation than Jacques
Alex

Answer:

A. Ahmed has a greater tangential speed than Jacques.

D. Jacques and Ahmed have the same angular speed.

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Kinematics of the merry-go-round

The tangential speed of the merry-go-round is calculated using the following formula:

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v is the tangential speed in meters/second (m/s)

ω is the angular speed in radians/second (rad/s)

R is the angular speed in meters (m)

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dJ = RJ   : Jacques distance to the axis of rotation

Problem development

We apply the formula (1)

v = ω*R

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vJ= ω*RJ  :  Jacques  tangential speed

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vA ˃ vJ

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Answer:

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Explanation:

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