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Leokris [45]
2 years ago
8

How many grams of barium sulfate are produced if 125 mL of .050 M sodium sulfate are reacted with excess barium nitrate in the f

ollowing reaction?
Ba(NO3)2 + Na2SO4 = BaSO4 + NaNO3
Chemistry
1 answer:
katrin [286]2 years ago
8 0

Answer:

2.79g

Explanation:

You might be interested in
2. What are the different areas of an electron cloud called?
Ghella [55]
Shells (electrons) - located in the cloud
nucleus- located in the center
energy level - is determined by the electron count ( level 1 - 2 electrons
level 2 - 8 electrons
level 3- 18 electrons)

5 0
3 years ago
For lunch, a patient consumed 3 oz of skinless chicken, 3 oz of broccoli, 1 medium apple, and 1 cup of nonfat milk (see Table 3.
Volgvan

Lunch of a patient has 3 oz skinless chicken, 3 oz of broccoli, 1 medium apple, and 1 cup of nonfat milk

Energy content of 3 oz skinless chicken is = 110 kcal

Energy content of 3 oz broccoli = 30 kcal

Energy content of 1 medium apple = 60 kcal

Energy content of 1 cup non-fat milk = 90 kcal

So the kilocalories of energy patient obtained from lunch

                   = 110 kcal+ 30 kcal + 60 kcal + 90 kcal = 290 kcal


3 0
2 years ago
Please help! Don’t know if I’m right!!
kompoz [17]

Answer:e

Explanation:

Bananas

4 0
3 years ago
Would the solubility for a substance increase by dissolving the solute with more water?
garik1379 [7]

Answer: Yes

Explanation:

With more water, the molecules of the substance have more water molecules to form bonds with, thus they are dissolved even faster at that same particular temperature.

For example: a mildly soluble substance like powdered milk get more dissolved in your teacup as water, the solvent is increased

8 0
2 years ago
Like all equilibrium constants, the value of Kw depends on temperature. At body temperature (37°C), Kw = 2.4 * 10-14. What are t
Aleksandr [31]

Answer:

pH = 6.8124

Explanation:

We know pH decreases with increase in temperature.

At room temperature i.e. 25⁰c pH of pure water is equal to 7

We know

Kw = [H⁺][OH⁻]...............(1)

where Kw = water dissociation constant

At equilibrium [H⁺] = [OH⁻]

So at 37⁰c i.e body temperature Kw = 2.4 × 10⁻¹⁴

From equation (1)

[H⁺]² = 2.4 × 10⁻¹⁴

[H⁺] = √2.4 × 10⁻¹⁴

[H⁺] = 1.54 × 10⁻⁷

pH  = - log[H⁺]

      = - log{1.54 × 10⁻⁷}

      = 6.812

5 0
2 years ago
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