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FromTheMoon [43]
2 years ago
5

A chunk of zinc is added to a solution of gold (III) nitrate to extract the gold. The reaction forms,

Chemistry
2 answers:
alina1380 [7]2 years ago
7 0

Answer:

it forms :

1. Gold ( Au )

2. Zinc nitrate ( Zn(NO3)2 )

Explanation:

When a chunk of zinc is added to a solution of gold (III) nitrate to extract the gold. The reaction forms Gold and Zinc nitrate .

it's a single displacement reaction,

here's the balanced equation for above reaction :

3 Zn + 2 Au(NO3)3 =》3 Zn(NO3)2 + 2 Au

Veseljchak [2.6K]2 years ago
4 0

Explanation:

Gold (AU)................

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Think about your morning from when you wake up until you arrive at school. Describe the forms of energy you encounter or use dur
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2 years ago
If a student has 125 mL of a 4.00 M CuSO4 solution and needs a 1.50 M solution, what volume do they need to dilute it to?
lara31 [8.8K]

Answer:

333.3mL

Explanation:

Using the formula as follows:

C1V1 = C2V2

Where;

C1 = initial concentration (M)

C2 = final concentration (M)

V1 = initial volume (mL)

V2 = final volume (mL)

According to the information provided in this question,

C1 = 4.00M

C2 = 1.50M

V1 = 125mL

V2 = ?

Using C1V1 = C2V2

4 × 125 = 1.5 × V2

500 = 1.5V2

V2 = 500/1.5

V2 = 333.3mL

Therefore, the CuSO4 solution needs to be diluted to 333.3mL to make 1.50 M solution.

3 0
2 years ago
Calcium hydroxide, Ca(OH)2, is an ionic compound with a solubility product constant, Ksp, of 6.5×10–6. Calculate the solubility
kari74 [83]

Answer: The solubility of this compound in pure water is 0.012 M

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Solubility product is defined as the equilibrium constant in which a solid ionic compound is dissolved to produce its ions in solution. It is represented as K_{sp}

The equation for the ionization of the  is given as:

Ca(OH)_2\rightarrow Ca^{2+}+2OH^-  

By stoichiometry of the reaction:

1 mole of  Ca(OH)_2 gives 1 mole of Ca^{2+} and 2 mole of OH^-

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S=0.012M

Thus solubility of this compound in pure water is 0.012 M

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