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FromTheMoon [43]
2 years ago
5

A chunk of zinc is added to a solution of gold (III) nitrate to extract the gold. The reaction forms,

Chemistry
2 answers:
alina1380 [7]2 years ago
7 0

Answer:

it forms :

1. Gold ( Au )

2. Zinc nitrate ( Zn(NO3)2 )

Explanation:

When a chunk of zinc is added to a solution of gold (III) nitrate to extract the gold. The reaction forms Gold and Zinc nitrate .

it's a single displacement reaction,

here's the balanced equation for above reaction :

3 Zn + 2 Au(NO3)3 =》3 Zn(NO3)2 + 2 Au

Veseljchak [2.6K]2 years ago
4 0

Explanation:

Gold (AU)................

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.<br> How many moles are there in 8.5 x 1024 molecules of sodium sulfate, Na2SO4?
NeTakaya

Answer: To solve this question, we need to use the Avogadro's Number, which is a constant first discovered by Amadeo Avogadro, an Italian scientist. He discovered that in a mole of a substance, there are 6,02*10²³ molecules. Using this relationship, we apply the following conversion factor:

So, 8,50 * 10²⁴ molecules of Na₂SO₃ represent 14,12 moles of Na₂SO₃

Explanation:

5 0
3 years ago
What is the method of seperating inmisible liquid<br>​
nikitadnepr [17]
Decantation is a process for the separation of mixtures of immiscible liquids or of a liquid and a solid mixture such as a suspension.
6 0
2 years ago
A 4.36 g sample of an unknown alkali metal hydroxide is dissolved in 100.0 ml of water. an acid-base indicator is added and the
Fofino [41]

Answer:

(a) 102.6g/mol

(b) Rubidium

Explanation:

Hello,

This titration is carried out by assuming that the volume of base doesn't have a significant change when the mass is added, thus, we state the following data a apply the down below formula to compute the molarity of the base solution:

V_{base}=0.1L; M_{acid}=2.5M, V_{acid}=0.017L\\V_{base}M_{base}=V_{acid}M_{acid}

Solving for the molarity of base we've got:

M_{base}=\frac{M_{acid}*V_{acid}}{V_{base}}=\frac{2.50M*0.017L}{0.1L} =0.425M=0.425mol/L

Now, we can compute the moles of the base as:

n_{base}=0.425mol/L*0.1L=0.0425mol

(a) Now, one divides the provided mass over the previously computed moles to get the molecular mass of the unknown base:

\frac{4.36g}{0.0425mol} =102.6g/mol

(b) Subtracting the atomic mass of oxygen and hydrogen, the metal's atomic mass turns out into:

102.6g/mol-16g/mol-1g/mol=85.6g/mol

So, that atomic mass dovetails to the Rubidium's atomic mass.

Best regards.

8 0
3 years ago
The average atomic weight of copper, which has two naturally occurring isotopes, is 63.5. One of the isotopes has an atomic weig
Darya [45]

<u>Answer:</u> The atomic weight of the second isotope is 64.81 amu.

<u>Explanation:</u>

Average atomic mass of an element is defined as the sum of atomic masses of each isotope each multiplied by their natural fractional abundance

Formula used to calculate average atomic mass follows:

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i     .....(1)

We are given:

Let the mass of isotope 2 be 'x'

Mass of isotope 1 = 62.9 amu

Percentage abundance of isotope 1 = 69.1 %

Fractional abundance of isotope 1 = 0.691

Mass of isotope 2 = 'x'

Percentage abundance of isotope 2 = 30.9%

Fractional abundance of isotope 2 = 0.309

Average atomic mass of copper = 63.5 amu

Putting values in equation 1, we get:

\text{Average atomic mass of copper}=[(62.9\times 0.691)+(x\times 0.309)]

x=64.81amu

Hence, the atomic weight of second isotope will be 64.81 amu.

4 0
3 years ago
Find the force it would take to accelerate an 800-kg car at a rate of 5m/s2.
laila [671]
Force= mass•acceleration

Force=800•5

Force=4000 N
3 0
2 years ago
Read 2 more answers
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